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3 years ago

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Morgan rolls a number cube, twice. If the number 1 shows up at least once, Morgan wins. Otherwise, Jaclyn wins. How much greater

is the probability that Morgan will win compared to Jaclyn winning?
A)1/3 B)7/18 C)4/9 D)2/3

1 answer:

alukav5142 [94]3 years ago

8 0

I am assuming from the answer choices that you meant Jaclyn's chances of winning.

There are 6 sides of a dice and it's rolled twice.
6×2=12

So while Morgan has a 2/12 chance (simplified that would be 1/6), Jaclyn has a 10/12 chance of winning (simplified that would be 1/3).

Therefore your answer would be A: 1/3

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Answer:

$x=33\\y=-41$

Step-by-step explanation:

Let:

$2x+y=25\hspace{5}(1)\\and\\4x+3y=9\hspace{5}(2)$

We need to eliminate one of the variables, so let's use elimination method. First multiply (1) by 2

$2*(1)\equiv\hspace{5}4x+2y=50$

Now subtract (2) from 2*(1) in order to eliminate x:

$2*(1)-(2)\\4x-4x+2y-3y=50-9\\-y=41$

Solving for y:

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3 years ago

Identify the solution set of the inequality using the given replacement set x < –2; {–5, –2.6, –2, –0.8, 1, 1.5}. A. {–5, –2.

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If x < - 2 and x ∈ { - 5, - 2.6, - 2, - 0.8, 1, 1.5 }
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The sum of 1/6,2/3, and 1/4 is

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¹³/₁₂

<h3>Further explanation</h3>

<u>Given:</u>

$\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = ? \ }$

A fraction represents part of a whole.
A fraction consists of a numerator and a denominator. i.e., $\boxed{ \ \frac{numerator}{denominator} \ }$ .
The numerator = the number of equal parts of a whole.
The denominator = the total number of parts that make up said whole.

From the problems above, the denominator or the bottom numbers are still different. We use the Least Common Multiple (or LCM) to equalize the denominator.

Multiples of 3: $\boxed{ \ \{3, 6, 9, 12, 15, ... \} \ }$
Multiples of 4: $\boxed{ \ \{4, 8, 12, 16, ... \} \ }$
Multiples of 6: $\boxed{ \ \{6, 12, 18, ... \} \ }$

Hence, the LCM for 3, 4, and 6 is 12.

We change the denominator for each fraction to 12.

$\boxed{ \ \frac{1}{6} \rightarrow \frac{multiply \ by \ 2}{multiply \ by \ 2} \rightarrow \frac{2}{12} \ }$

$\boxed{ \ \frac{2}{3} \rightarrow \frac{multiply \ by \ 4}{multiply \ by \ 4} \rightarrow \frac{8}{12} \ }$

$\boxed{ \ \frac{1}{4} \rightarrow \frac{multiply \ by \ 3}{multiply \ by \ 3} \rightarrow \frac{3}{12} \ }$

Then we continue adding fractions.

$\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = \frac{2}{12} + \frac{8}{12} + \frac{3}{12} \ }$

$\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = \boxed{ \ \frac{13}{12} \ } \ }$

Thus, the result is $\boxed{ \ \frac{13}{12} \ or \ 1\frac{1}{12}\ }$

<h3>Learn more</h3>

²/₇m - ¹/₇= ³/₁₄ solve step by step brainly.com/question/4853649
100 is 1/10 of what? brainly.com/question/96535
Mr. Frye distributed his money equally among his 4 children for their weekly allowance brainly.com/question/13174288#

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