1 cup per 8 oz
48/6 = 8
every 1 cup of water 8 oz of tomato paste.
We find the value of N₀ since we are provided with initial conditions.
The condition is that, at time t = 0, the amount of substance contains originally 10 grams.
We substitute:
10 = N₀ (e^(-0.1356)*0)
10 = N₀ (e^0)
N₀ = 10
When the substance is in half-life (meaning, the half of the original amount), it contains 5 grams. We solve t in this case.
5 = 10 e^(-0.1356*t)
0.5 = e^(-0.1356*t)
Multiply natural logarithms on both sides to bring down t.
ln(0.5) = -0.1356*t
Hence,
t = -(ln(0.5))/0.1356
t ≈ 5.11 days (ANSWER)
Answer:
The answer should be -4/1 or just -4.
Step-by-step explanation:
y/x
The change in y is reducing by 4. The change in x is adding 1
A chart would include
x, y
-2, 0
-1, 1
0, 2
1, 3
2, 4
The graph would look like this (Image attached)
PRQ and QRS should add to PRS
(3x-8)+(2x+6)=98
5x-2=98
5x=100
x=20
Plug 20 into both expressions:
3(20)-8
60-8
52 degrees= PRQ. <===========
2(20)+6
40+6
46 degrees= QRS. <==========
