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3 years ago

PLEASE HELP PLEASE PLEASE PLEASE

Mathematics

1 answer:

Leviafan [203]3 years ago

4 0

X+27=4x+12

X+15=4x

15=3x

5=x

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Construct a rhombus whose diagonals are 6.2cm 8.4cm long

Vladimir [108]

Answer:

you have to construct a rombus

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3 years ago

URGENT HELP PLEASE

sammy [17]

Answer:

slope1 : 7, slope 2 = 3 solution: (2,5)

Step-by-step explanation:

I simplify some steps

pair 1: x1 0 2

y1 -9 5 ........ -9, y1 intercept

pair 2: x2 0 2

y2 -1 5 ........ -1, y2 interept

2 pairs meet at (2,5)

y=7x-9 ......A

y=3x-1 ......B

A-B 0=4x-8

4x=8

x=2

y=5

slope 1=( y2-y1) / (x2-x1) = (5- -9)/(2-0) = 14/2 =7

slope 2 = (5 - -1) / (2 - 0) = 6/2 = 3

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3 years ago

an auto transport truck holds 12 cars. A car dealer plans to bring in 1150 new cars in June and July. If an auto transport truck

marusya05 [52]

Answer: 96 truckloads, 95 will be full, the last on will have 10 cars

Step-by-step explanation: 1150/12= 95.888> 95*12=1140, 1140+10=1150

6 0

3 years ago

Please Help! This is a trigonometry question.

liraira [26]

$\large\begin{array}{l} \textsf{From the picture, we get}\\\\ \mathsf{tan\,\theta=\dfrac{2}{3}}\\\\ \mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{2}{3}}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\qquad\mathsf{(i)} \end{array}$

$\large\begin{array}{l} \textsf{Square both sides of \mathsf{(i)} above:}\\\\ \mathsf{(3\,sin\,\theta)^2=(2\,cos\,\theta)^2}\\\\ \mathsf{9\,sin^2\,\theta=4\,cos^2\,\theta}\qquad\quad\textsf{(but }\mathsf{cos^2\theta=1-sin^2\,\theta}\textsf{)}\\\\ \mathsf{9\,sin^2\,\theta=4\cdot (1-sin^2\,\theta)}\\\\ \mathsf{9\,sin^2\,\theta=4-4\,sin^2\,\theta}\\\\ \mathsf{9\,sin^2\,\theta+4\,sin^2\,\theta=4} \end{array}$

$\large\begin{array}{l} \mathsf{13\,sin^2\,\theta=4}\\\\ \mathsf{sin^2\,\theta=\dfrac{4}{13}}\\\\ \mathsf{sin\,\theta=\sqrt{\dfrac{4}{13}}}\\\\ \textsf{(we must take the positive square root, because }\theta \textsf{ is an}\\\textsf{acute angle, so its sine is positive)}\\\\ \mathsf{sin\,\theta=\dfrac{2}{\sqrt{13}}} \end{array}$

________

$\large\begin{array}{l} \textsf{From (i), we find the value of }\mathsf{cos\,\theta:}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{2}\,sin\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\diagup\!\!\!\! 2}\cdot \dfrac{\diagup\!\!\!\! 2}{\sqrt{13}}}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\sqrt{13}}}\\\\ \end{array}$

________

$\large\begin{array}{l} \textsf{Since sine and cosecant functions are reciprocal, we have}\\\\ \mathsf{sin\,2\theta\cdot csc\,2\theta=1}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{sin\,2\theta}\qquad\quad\textsf{(but }}\mathsf{sin\,2\theta=2\,sin\,\theta\,cos\,\theta}\textsf{)}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\,sin\,\theta\,cos\,\theta}}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\cdot \frac{2}{\sqrt{13}}\cdot \frac{3}{\sqrt{13}}}} \end{array}$

$\large\begin{array}{l} \mathsf{csc\,2\theta=\dfrac{~~~~1~~~~}{\frac{2\cdot 2\cdot 3}{(\sqrt{13})^2}}}\\\\ \mathsf{csc\,2\theta=\dfrac{~~1~~}{\frac{12}{13}}}\\\\ \boxed{\begin{array}{c}\mathsf{csc\,2\theta=\dfrac{13}{12}} \end{array}}\qquad\checkmark \end{array}$

<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2150237

$\large\textsf{I hope it helps.}$

Tags: <em>trigonometry trig function cosecant csc double angle identity geometry</em>

</span>

8 0

3 years ago

Nut C fits on Bolt C. Nut B fits on Bolt B. Nut A fits on Bolt A. Bolt C is larger than Bolt B. Bolt A and Bolt B are exactly th

Alborosie

Answer:

Bolt A will fit Nut A and Nut B

Step-by-step explanation:

We have the following statements:

Nut C fits on Bolt C.

Nut B fits on Bolt B.

Nut A fits on Bolt A.

Bolt C is larger than Bolt B.

Bolt A and Bolt B are exactly the same.

Then we can say that Bolt A will fit Nut A and Nut B...

4 0

4 years ago