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Monica [59]
3 years ago
9

PLEASE HELP PLEASE PLEASE PLEASE

Mathematics
1 answer:
Leviafan [203]3 years ago
4 0

X+27=4x+12

X+15=4x

15=3x

5=x

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The school chorus has has 52 students, which represents 26% of the seventh graders. How many students are in the seventh grade?
s344n2d4d5 [400]
200 students 52/200 x 100 = 52%
6 0
3 years ago
The base of a triangle exceeds the height by 4 inches. if the area is 178.5 square inches, find the length of the base and the h
Elanso [62]
A = 1/2 * b * h
A = 178.5
b = h + 4

178.5 = 1/2 * (h + 4) * h
357 = h^2 + 4h
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(h - 17)(h + 21) = 0

h - 17 = 0
h = 17

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h = -21 .....not this one because it is negative

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6 0
3 years ago
52 ÷ 5 + (42 ∙ 2) – 36 ÷ 9
balandron [24]
The answer to that is 21
4 0
3 years ago
Read 2 more answers
How are common denominator and common multiples alike and different
miskamm [114]
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A common multiple is when two numbers can be multiplying to the same number. Ex) A common multiple of 3 & 4  is 12
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8 0
3 years ago
Find the measure of each side indicated round to the nearest 10th
earnstyle [38]

Answer:

20) 30°; 21) 21,1; 22) 6,2

Step-by-step explanation:

For the first image, you have to do <em>csc</em><em>⁻</em><em>¹</em><em> </em><em>2</em><em> </em>[OR <em>sin</em><em>⁻</em><em>¹</em><em> </em><em>½</em>] because you are solving for an angle measure. When evaluated, you get 30°.

For the second image, you have to do <em>13sec</em><em> </em><em>52</em><em>°</em><em> </em><em>=</em><em> </em><em>x</em><em> </em>[OR <em>13\</em><em>cos</em><em> </em><em>52</em><em>°</em><em> </em><em>= x</em>]. When evaluated, you get an approximate measure of 21,1.

For the third image, you have to do <em>6csc</em><em> </em><em>75</em><em>°</em><em> </em><em>=</em><em> </em><em>x</em><em> </em>[OR <em>6</em><em>\</em><em>sin</em><em> </em><em>75</em><em>°</em><em> </em><em>= x</em>]. When evaluated, you get an approximate measure of 6,2.

Extended information on Trigonometric Ratios

O\H = sin θ

A\H = cos θ

O\A = tan θ

H\A = sec θ

H\O = csc θ

A\O = cot θ

I am joyous to assist you anytime.

4 0
3 years ago
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