2 years ago

Solve for x. Round to the nearest tenth of a degree, if necessary.

Mathematics

1 answer:

MissTica2 years ago

4 0

Answer:

x ≈ 54.8°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = $\frac{opposite}{adjacent}$ = $\frac{PQ}{QR}$ = $\frac{7.1}{5}$ , then

x = $tan^{-1}$ ( $\frac{7.1}{5}$ ) ≈ 54.8° ( to the nearest tenth )

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Someone Please help me..What must the value of x be in order for the figures below to be similar?

Ksenya-84 [330]

Answer:

16 cm

Step-by-step explanation:

x+x

8+8

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2 years ago

If a spherical ball is enlarged so that its surface area is 9 times greater than its original surface area, then the original ra

luda_lava [24]

The surface area of a sphere is $A = 4 \pi r^{2}$ and if the original S.A was is enlarged to have it 9 times greater, the radius would be multiplied by 3 or roughly 2.99626 rounded off to 3.0.

For example, let us assign values.
Let A=90

A= 90*9 = 810

$90 = 4 \pi r^{2} 

$ and $810 = 4 \pi r ^{2}$

the first r is 2.68 and the second r is 8.03

then, $\frac{8.03}{2.68} = 2.99626$ or rounded off to 3.