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san4es73 [151]
3 years ago
12

You are ima room with other students and are asked to get in groups of 3. When finished, there are 21 groups of 3. How manny stu

dents are in the room?
Mathematics
2 answers:
kap26 [50]3 years ago
7 0

Answer:

63

Step-by-step explanation:

21 goups of 3 students each.

21 * 3 = 69

Answer: There are 63 students.

ivolga24 [154]3 years ago
6 0

There are 63 students in the room, this is because 21 time 3 gives you 63.

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Answer:

C

Step-by-step explanation:

180-33-88 equals 59 and in order for the two triangles to be congruent it would need to be 58, which is present as an angle in the other triangle

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Select the expression that is equivalent to (m2-16)
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B because we’re looking at factoring perfect squares and the the square root of m^2 or 1^2 is 1 and that of 16 is 4
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Player pays a fee, then reaches into a large jar and picks out a ball. The jar contains one ball for each letter of the alphabet
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Answer:

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Prove that 2n^3 + 3n^2 + n is divisible by 6 for every integer n > 1 by mathematical induction. (7 marks)
notka56 [123]

Answer:

The answer is True

Step-by-step explanation:

A <em>mathematical induction</em> consists in only 2 steps:  

<u>First step</u>: Show the proposition is true for the first one valid integer number.

<u>Second step</u>: Show that if any one is true then the next one is true  

Finally, if first step and second step are true, then the complete proposition is true.

So, given 2*n^3+3*n^2+n

First step: using and replacing n=2 (the first valid integer number >1)

2*(2)^3 +3*(2)^2+2=30

\frac{30}{6} =5

As the result is an integer number, so the first step is true.

Second step: using any next number, n+1, let it replace

2*(n+1)^3+3*(n+1)^2+(n+1)\\2*(n^3+3*n^2+3*n+1)+3*(n^2+2*n+1)^2+(n+1)\\2*n^3+6*n^2+6*n+2+3*n^2+6*n+3+n+1\\(2*n^3+3*n^2+n)+(6*n^2+12*n+6)

As the First step is true, we know that

2*n^3+3*n^2+n=6*k,

So let it replace in the previous expression

6*k+6*(n^2+2*n+1)\\6*[k+(n^2+2*n+1)]

Finally

\frac{6*[k+(n^2+2*n+1)]}{6} =k+(n^2+2*n+1)

where the last expression is an integer number

So the second step is true, and the complete proposition is True

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