Think of 10^2, 10^1, and 10^0 as x^2, x^1, and x^0.
When you add polynomials, you can only combine like terms.
When you add expanded numbers, you can only combine like powers of 10.
123 + 423 =
= (100 + 20 + 3) + (400 + 20 + 3)
= (1 * 10^2 + 2 * 10^1 + 3 * 10^0) + (4 * 10^2 + 2 * 10^1 + 3 * 10^0)
= (1 * 10^2 + 4 * 10^2) + (2 * 10^1 + 2 * 10^1) + (3 * 10^0 + 3 * 10^0)
= 5 * 10^2 + 4 * 10^1 + 6 * 10^0
= 500 + 40 + 6
= 546
Answer:
Step-by-step explanation:
Let s be the number of students in each of 6 buses. Then there are 6s students in all buses.
Five of the students ride in a van. In total, in a van and in buses there are 
students.
There are 221 students on a filed trip. So,
Okay so let's make this fraction bigger. 2/3 x 2 would equal 4/6 which means megan uses 1/6 per cup of trail mix. so if she wanted to make 9 batches of trail mix she would use 2 1/6 but let's make that into an improper fraction.. aka 13/6 .. we cannot simplify that so megan would need 2 1/6 cups of almonds
<span>cos x = [ e^(ix) - e^(-ix) ] / 2i along with [ A - B ]^5 =
( A^5 - B^5) - 5 AB ( A^3 - B^3) + 10 A²B² (A - B )...A = e^(ix) , B = e^(-ix)
[ cos x ] ^5 = (1/32i) { [ e^(5ix) - e^(-5x) ] - 5 [ ( e^(3ix) - e^(-3ix) ] + 10 [ e^(ix) - e^(-ix) ] }
= ( 1 / 16 ) { cos 5x - 5 cos 3x + 10 cos x }.....much faster</span>
