<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection )
p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = 
Hence, p(getting 2 good coil for two selection) = 
Distance Formula: 
Apply the points: 
Solve: 
Since the square root of 218 cannot be simplified, the answer is

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Answer:
i......dont........know.... :)
Step-by-step explanation:
yup
Answer:
19.75
Step-by-step explanation:
while she divided the remainder 3 (then you bring down the 0) she accidentaly put 30 in 19.30 so thats why
while the correct way is to keep going with the equation until you have no remainder