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jasenka [17]
3 years ago
14

Please help! algebra 1 math! whoever gets right is Brainliest! (10 points)

Mathematics
2 answers:
Inga [223]3 years ago
7 0
I believe that 7 5/4 is the answer.
EleoNora [17]3 years ago
3 0
Rewrite as (7^5)^(1/4) which becomes 7^5/4
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HELPPPP MEEEE PLEASE!!!!​
creativ13 [48]

Answer:

Step-by-step explanation:

3 0
2 years ago
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
IgorLugansk [536]

Answer:

a) 0.32 = 32% probability that your bid will be accepted

b) 0.72 = 72% probability that your bid will be accepted

c) An amount in excess of $15,400.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,400 and $15,400.

This means that a = 10400, b = 15400

a. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)?

You will win if the competitor bids less than 12000. So

P(X \leq 12000) = \frac{12000 - 10400}{15400 - 10400} = 0.32

0.32 = 32% probability that your bid will be accepted

b. Suppose you bid $14,000. What is the probability that your bid will be accepted?

You will win if the competitor bids less than 14000. So

P(X \leq 14000) = \frac{14000 - 10400}{15400 - 10400} = 0.72

0.72 = 72% probability that your bid will be accepted

c. What amount should you bid to maximize the probability that you get the property (in dollars)?

His bid is uniformly distributed between $10,400 and $15,400.

So, to maximize the probability that you get the property, you should bid an amount in excess of $15,400.

6 0
3 years ago
Solve this systems of equation word problem. please
agasfer [191]
2b+h = 4.82
b+2h = 3.70
multiply the second equation by 2:
2b + 4h = 7.40
subtract the first equation from it:
3h = 2.58
h = 0.86
5 0
3 years ago
Your friend Albert has invented a game involving two ten-sided dice. One of the dice has threes, fours, and fives on its faces,
guapka [62]

Answer:

d. 11.6

Step-by-step explanation:

The results of the first die and the second one are independent to each other. The expected value of Z is obtained, therefore, by summing the expected values of both X and Y, because Z = X+Y and X and Y are independent. As a result \mu_z = \mu_x + \mu_y = 3.6+8.0 = 11.6 .

4 0
3 years ago
Which of the following statements are true about the function y = 3x?
dolphi86 [110]

Answer:

I believe the answer is The constant of variation is y is 6 when x is 2.

6 0
3 years ago
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