All categories

3 years ago

The outside temperature is -3°F and falling at a rate of 2 degrees per hour. What will the temperature be in 5 hours?

Mathematics

1 answer:

Kitty [74]3 years ago

4 0

In five hours the temperature would be -13 degrees F. Hope this helps.

You might be interested in

Is PQR-XYZ? If so, name which similarity postulate or theorem applies.

vagabundo [1.1K]

Answer:

Step-by-step explanation:

I think similar aa

5 0

3 years ago

The admission fee at a small rodeo is $8.50 for children and $15.00 for adults. On a certain day, 400 people enter the rodeo and

zavuch27 [327]

Answer:

Step-by-step explanation:

5 0

2 years ago

Rida and elisa are each paid by the hour. rida worked 5 1\2. hours and earned 77. elisa worked 3 3\4 HOURS AND EARNED 60. WHOSE

skad [1K]

Rida:
5 1/2 :77
5.5 : 77
Divide both sides by 5.5 to get $/hour:
1:14

Elisa:
3 3/4:60
3.75:60
Divide both sides by 3.75 to get $/hour:
1:16

16 is bigger than 14 so Elisa earns more.

Hope this helps :)

5 0

3 years ago

What is the slope of the line that passes through the points (-4, 6) and (2, 4)?

Tpy6a [65]

Your answer will be a

6 0

3 years ago

Read 2 more answers

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0

3 years ago