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Elan Coil [88]
2 years ago
14

In the figure below, XZ=35 and YZ=17. Find XY.

Mathematics
2 answers:
taurus [48]2 years ago
7 0

\sf \: XZ=XY+YZ \\  \tt \: [by \: segment \: addition \: postulate]

\bf \: 35=XY+17

\bf \: 35 - XY = 17

\bf \:   - XY = 17 - 35

\bf \:  - XY =  - 18

\boxed{ \rm \: XY = 18}

balandron [24]2 years ago
4 0

Answer:

XY = 18

Step-by-step explanation:

XY → XZ - YZ      [ here given XZ is 35 and YZ is 17 ]

XY → 35 - 17        [ subtracting ]

XY → 18               [ final answer ]

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6 0
3 years ago
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Angelina_Jolie [31]

Answer:

n = all real numbers

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7n+12=1/2(14n+24)

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14n+24 = 14n + 24

subtract 14n from each side

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3 0
3 years ago
Use the drop-downs to identify the domain and range of the following relation.
Orlov [11]

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5 0
3 years ago
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Solving systems of equations using any method
andreev551 [17]

Answer:

x = 5 , y = 2

Step-by-step explanation:

Solve the following system:

{y = (7 x)/5 - 5 | (equation 1)

{y = (3 x)/5 - 1 | (equation 2)

Express the system in standard form:

{-(7 x)/5 + y = -5 | (equation 1)

{-(3 x)/5 + y = -1 | (equation 2)

Subtract 3/7 × (equation 1) from equation 2:

{-(7 x)/5 + y = -5 | (equation 1)

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Multiply equation 1 by 5:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 2 by 7/4:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+y = 2 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{-(7 x)+0 y = -35 | (equation 1)

{0 x+y = 2 | (equation 2)

Divide equation 1 by -7:

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Collect results:

Answer:  {x = 5 , y = 2

7 0
3 years ago
Which set of lengths are not the side lengths of a right triangle? (A-28, 45, 53) (B-13, 84, 85) (C-36, 77, 85) (D-16, 61, 65) [
nikklg [1K]
Side lengths 16, 61, and 65 are not part of a right triangle.

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6 0
3 years ago
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