Answer:
The values of
so that
have vertical asymptotes are
,
,
,
,
.
Step-by-step explanation:
The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of
so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is
. Then, the vertical asymptotes associated with function cosecant are located in the values of
of the form:
, 
In other words, the values of
so that
have vertical asymptotes are
,
,
,
,
.
The number of hours spent playing video games is the independent variable and cumulative grade point average is the dependent variable.
<h3>What is an independent variable?</h3>
An independent variable simply means the variable that's changed to test the effect on the dependent variable.
Here, the number of hours spent playing video games is the independent variable and cumulative grade point average is the dependent variable.
This is because the number of hours is being used to predict cumulative grade point average.
Learn more about variables on:
brainly.com/question/25223322
#SPJ1
Given,
Cylinder A has a volume of 6 cubic units
and height =3 units
The radius of cylinder A,
![\begin{gathered} r=\sqrt[]{\frac{V}{\pi h}} \\ =\sqrt[]{\frac{6}{3\pi}} \\ =0.8 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20r%3D%5Csqrt%5B%5D%7B%5Cfrac%7BV%7D%7B%5Cpi%20h%7D%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B%5Cfrac%7B6%7D%7B3%5Cpi%7D%7D%20%5C%5C%20%3D0.8%20%5Cend%7Bgathered%7D)
To find the volume of a cylinder B

Thus the volume of cylinder B is 6.03
Answer:
'''
Step-by-step explanation:
Let's start with what we know:
Smaller canvas:
Length (

) = 3ft
Width (

) = 5ft
Larger canvas:
Length (

) = ?
Width (

) = 10ft
Since these are similar rectangles, we can cross-multiply to calculate the missing length. Here's that formula:

So let's plug it all in from above:

Now we cross multiply by multiplying the top-left by the bottom-right and vice versa:


Now divide each side by 5 to isolate


The 5s on the right cancel out, leaving us with:

So the length of the larger canvas is
6 ft