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lapo4ka [179]
3 years ago
6

Suppose that coin 1 has probability 0.7 of coming up heads, and coin 2 has probability 0.6 of coming up heads. If the coin flipp

ed today comes up heads, then we select coin 1 to flip tomorrow, and if it comes up tails, then we select coin 2 to flip tomorrow. If the coin initially flipped is equally likely to be coin 1 or coin 2, then what is the probability that the coin flipped on the third day after the initial flip is coin 1? Suppose that the coin flipped on Monday comes up heads. What is the probab
Mathematics
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

0.13

Step-by-step explanation:

this is my answer it will help you

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3 years ago
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Nataly_w [17]

Answer:

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Step-by-step explanation:

First find the LCM of 6 and 8:24

So the two given fractions are 20/24, and 21/24

Since the the fractions will become decimals with the denominator 24, choose another denominator: 48

So the two given fractions are 40/48 and 42/48.

Even this denominator isn't possible so continue with different denominators.

As I notice, that each multiple increases by 1...

20-21, 40-42, 60-63, 80-84, and 100-105.

100-105 is the only numerator that has 4 numbers in-between so, the four fractions between 5/6 and 7/8 are: 101/120, 102/120, 103/120, and 104/120.

And the 2 given fractions are 100/120 and 105/120.

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larisa [96]
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8 0
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Annette [7]

Answer:

I believe the correct answer would be A: 3/5 = 60

Step-by-step explanation:

Firstly, the second option is wrong because 0.06 would be 6 hundredths, so that is wrong, the third option would be incorrect because 0.002 would equal 2 thousandths so that is also wrong, and the fourth option would be 25% instead of 75%, so your answer should be A.

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