Answer:
vertical asymptote at x = 7
horizontal asymptote at y = 6
Step-by-step explanation:
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.
solve:
x
−
7
=
0
⇒
x
=
7 is the asymptote
Horizontal asymptotes occur as
lim
,f(x)→
c(a constant)
x
→
±
∞
divide terms on numerator/denominator by x
f
(
x
)
=
5/
x
+6=
5
/x
+
6
x/
x
−
7
/x 1
−
7/
x
as
x
±
∞
,
f
(
x
)
→
0
+6
1
−
0
⇒
y
=
6 is the asymptote
graph{((5)/(x-7))+6 [-20, 20, -10, 10]}
Pythagorean Theorem can be used only for right triangles.
(leg1)² +(leg2)² = hypotenuse ²
So, answer is the right triangle B.
<span> 10^-4 is the answer</span>
Answer:
A
Step-by-step explanation:
(fg)(x) = f(x) × g(x)
= (x - 8)(x² + x - 1)
Each term in the second factor is multiplied by each term in the first factor, that is
x(x² + x - 1) - 8(x² + x - 1) ← distribute both parenthesis
= x³ + x² - x - 8x² - 8x + 8 ← collect like terms
= x³ - 7x² - 9x + 8 → A
There are no restrictions on the domain.
