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4 years ago

FREE POINTS!!!!!!!!!!! 2+3(8-2)= x

Mathematics

2 answers:

alexandr402 [8]4 years ago

8 0

Answer:

18x+2

Step-by-step explanation:

grandymaker [24]4 years ago

5 0

The answer would be 18x+2

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What is a linear function that relates to this table?

natima [27]

The linear function should be y=2 i apologize if i am wrong

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4 years ago

The cube of the sum of 4 and 9 times x divided by the product of 5 times x and the difference of x and 1

Burka [1]

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3 years ago

Two certificates of deposit pay interest at rates that differ by 4%. Money invested for one year in the first CD earns $175 inte

wolverine [178]

We are told that the principle is the same for both investments so we can say:

315=P(r+4)/100 and 175=Pr/100 solving both for P you have:

P=31500/(r+4) and P=17500/r since P=P:

17500/r=31500/(r+4)

175(r+4)=315r

175r+700=315r

-140r+700=0

-140r=-700

r=5

So the rates are 5% and (5+4)=9%

check...

P(9/100)=315 and P(5/100)=175

P=31500/9 and P=17500/5

P=157500/45 and P=157500/45

So P=P

note: P=$3500

3500(9/100)=$315

3500(5/100)=$175

5 0

3 years ago

Find the missing side of a triangle when one side is 3.16 and the other is 3

WITCHER [35]

Answer:

0.992774 ≅ .993

Step-by-step explanation:

a²+b²=c²

a=x

b=3

c=3.16

x²+3²=3.16²

x²+9=9.9856

x²=.9856

x=0.992774

x≅0.993

6 0

4 years ago

The general equation for a circle is a(x^2 + y^2) + bx + cy + d = 0. There is exactly one circle passing through the points (3,-

lidiya [134]

Answer:

The equation for this circle is 2c(x²+y²) - 8cx + cy = 0

Step-by-step explanation:

We can solve this problem replacing each of the points in the general equation and then solving the system of equations.

The fact that the circle passes by the point (3,-2) means that when x = 3, y = -2. So:

$a(3^{2} + (-2)^2) + 3b - 2c + d = 0$

$13a+ 3b - 2c + d = 0$

For (1, -2)

$a(1^{2} + (-2)^2) + b - 2c + d = 0$

$5a + b - 2c + d = 0$

For (0,0)

$a(0^{2} + (0)^2) + 0b - 0c + d = 0$

$d = 0$

Now we have to find a,b,c, from the following equations

13a+ 3b - 2c = 0

5a + b - 2c = 0

Since we have variables and 2 equations, i am going to write a and b as functions of c.

13a + 3b = 2c

5a + b = 2c

I will write b in the second equation as a function of a and c, and replace in the first equation

b = 2c - 5a

---------

13a + 3(2c-5a) = 2c

13a + 6cc -15a = 2c

-2a = -4c *(-1)

2a = 4c

a = 2c

-----------

b = 2c - 5a

b = 2c - 5(2c)

b = -8c

The solution for the system is (a,b,c) = (2c, -8c, c). So the equation for this circle is 2c(x²+y²) - 8cx + cy = 0

6 0

3 years ago