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Gemiola [76]
4 years ago
14

What would i do? I’m very confused on where to even start.

Mathematics
2 answers:
slavikrds [6]4 years ago
7 0

Answer:

just ask your question and post it and somebody will help with the answer

Step-by-step explanation:

hodyreva [135]4 years ago
6 0
You just type out the key words in your assignment, the assignment must relate to the subject you choose

Then you select the amount of points, and then you press “ask” or some green button and boom! Done

Hope this helps you ♥︎

You might be interested in
Two numbers less than 8 that<br> have 3 as their GCF
Anarel [89]

Answer:

3 and 6

Step-by-step explanation:

GCF's or greatest common factors of numbers 1 to 8

1 : 1

2 : 1, 2

3: 1 , 3

4 : 1, 2, 4

5 : 1, 5

6 : 1, 2, 3, 6

7 : 1, 7

8 : 1, 2, 4, 8

3 and 6 have 3 as their GCF

4 0
3 years ago
Helpppppppppppppppppppppppppppppp! please someone?
Minchanka [31]

Answer:

-  \frac{16}{ 25 } \div ( -  \frac{4}{5} ) =  \frac{16}{25}  \times  \frac{5}{4}  =  \frac{4}{5}  \:or \: 0.8

4 0
3 years ago
Read 2 more answers
What is the answer and how do you solve <br><br><br> 21x^3/3x^−1
Sunny_sXe [5.5K]

Answer:

  as written: 7x^2

  perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

  \dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2

___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

  21x^3/(3x^-1)

then the simplification is ...

  \dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4

_____

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^b/a^c = a^(b-c)

6 0
3 years ago
The quotient of a number and four decreased by ten is two. What is the number
MakcuM [25]
X divided by 4 - 10=2 x=48
3 0
3 years ago
Joseph claims that a scatterplot in which the y-values increase as the x-values increase must have a linear association. Amy cla
My name is Ann [436]

Answer: Choice C

Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.

======================================================

Explanation:

Just because the data points trend upward (as you go from left to right), it does not mean the data is linearly associated.

Consider a parabola that goes uphill, or an exponential curve that does the same. Both are nonlinear. If we have points close to or on these nonlinear curves, then we consider the scatterplot to have nonlinear association.

Also, you could have points randomly scattered about that don't fit either of those two functions, or any elementary math function your teacher has discussed so far, and yet the points could trend upward. If the points are not close to the same straight line, then we don't have linear association.

-----------------

In short, if the points all fall on the same line or close to it, then we have linear association. Otherwise, we have nonlinear association of some kind.

Joseph's claim that an increasing trend is not enough evidence to conclude the scatterplot is linear or not.

8 0
3 years ago
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