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goldfiish [28.3K]
3 years ago
9

What is the answer and how do you solve 21x^3/3x^−1

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

  as written: 7x^2

  perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

  \dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2

___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

  21x^3/(3x^-1)

then the simplification is ...

  \dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4

_____

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^b/a^c = a^(b-c)

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4 0
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Please help me on these! I really don't get it and I have to get them done!
Mandarinka [93]
Hey there :)

All these shapes are known as a rhombus.
The are formula of a rhombus is \frac{(side1)(side2)}{2}

1st ) The area is given = 48 in² 
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Apply the formula to find x 
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Divide by 16 on either side to isolate x
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Check:
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2nd ) Area is given = 48 ft²
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Apply the formula to find x 
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48 = 4x

Divide by 4 on either side
\frac{48}{4} = \frac{4x}{4}
12 = x 

Check:
Area = \frac{(4+4)(12)}{2}
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3rd ) Given diagonals are 19 ft and 38 ft
Area = \frac{(19)(38)}{2}
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         = 361 ft²

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3 years ago
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