Step-by-step explanation:
According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B0%7D%7B4%7D%20%3D%200%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B4%7D%CF%80%20%3D%20%5Cfrac%7B%CF%80%7D%7B2%7D)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is. Moreover, ALL <em>tangent</em>,<em> </em><em>secant</em>, <em>cosecant</em>, and <em>cotangent</em> functions have NO AMPLITUDE.
I am joyous to assist you anytime.
Answer:
Step-by-step explanation:
65.00 - 31.25 - 16.50 = $17.25
<span>7n + 4 - 5n <= 2(n+2)
Let's simplify these expression first
2n + 4 <= 2(n + 2)
2(n +4) = 2n + 4
The LHS and RHS expressions are the same but the inequality says contrary
Hence 2n + 4 is not less than but equal to 2(n + 2).
7+ 6a >= -4(2-a) - 2a
-4(2-a) - 2a = -8 + 4a - 2a = -8 + 2a. It should be obvious that 7 +6a is greater than the RHS expression.
Suppose a= 2 then we have 7 + 6(2) = 19 while -8 + 2(2) = - 8 + 4 = -4 So it follows that 7 + 6a >= -4(2-4) -2a
4x >= 8. The expression is always true so the equal to option is out.</span>
Answer:
It's first term is - 6. Fifth term is 6
