H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
Answer:
Debra Goforth's savings account shows a balance of $904.51 on March 1. The same day, she ... of $904.51 on March 1. The same day, she made a deposit of $375.00 to the account. She also made deposits of $500.00 on April 1 and May 1. The bank pays interest at a rate of 5.5 percent compounded daily.
Step-by-step explanation:
Hope this helps!
Answer:
A) 2x + 5
Step-by-step explanation:
First, turn 2x - y = 16 into 2x - 16 = y by adding the <em>y</em> on both sides and subtracting 16 from both sides.
You'll see that option A is the only option that matches the original function that we're comparing to.
Graphs will always be parallel to each other if they have the same slope, and both these functions have the same slope of 2.