What is the equation of the line that has a y-intercept of 5 and is parallel to

Mathematics

1 answer:

victus00 [196]3 years ago

7 0

Answer:

A) 2x + 5

Step-by-step explanation:

First, turn 2x - y = 16 into 2x - 16 = y by adding the y on both sides and subtracting 16 from both sides.

You'll see that option A is the only option that matches the original function that we're comparing to.

Graphs will always be parallel to each other if they have the same slope, and both these functions have the same slope of 2.

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What is (6,1) negative one half in point slope form

matrenka [14]

Answer: y - 1 = $-\frac{1}{2}$ (x - 6)

Step-by-step explanation:

Point-Slope form: y - y₁ = m(x - x₁) where m is slope and (x₁, y₁) is the point

m = $-\frac{1}{2}$ (x₁, y₁) = (6, 1)

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Charra [1.4K]

Answer:

More Than

Step-by-step explanation:

According to the given statement:

This year the club earned $20 more than twice what it earned last year. Let x represent the amount raised last year.

The two words in this problem which tell us about the operation are "More Than"

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3 years ago

I am currently working on Trigonometry, but unfortunately I am having a hard time. Here are some of my questions I've answered s

Novosadov [1.4K]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}\\\\
-------------------------------\\\\
cos(\theta)=\cfrac{\sqrt{3}}{3}\cfrac{\leftarrow adjacent=a}{\leftarrow hypotenuse=c}
\\\\\\
\textit{using the pythagorean theorem}\implies c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b
\\\\\\
\pm\sqrt{3^2-(\sqrt{3})^2}=b\implies \pm\sqrt{6}=b$

now the root gives us the +/-, which is it? well, we know the sine is negative, so the "b" value must be negative, so it has to be -√6 = b

thus $\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(\theta)=-\cfrac{\sqrt{6}}{3}$