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Korvikt [17]
4 years ago
14

ANSWER MY QUESTION I WILL GIVE YOU A BRAINLIEST

Mathematics
2 answers:
storchak [24]4 years ago
4 0
You would do the opposite of what he stated. So you would do $22.20 divided by 12. Which would be $1.85. So a carton of eggs costs $1.85. You would then multiply $1.85 by 7 and get $12.95.
vredina [299]4 years ago
3 0
22.20/12=1.85
1.85•7=12.95
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How many feet are in 100 inches? Write your answer two ways: in feet and inches and in feet only
jolli1 [7]

Answer: 8 ft and 4 in, 8 1/3 ft

Step-by-step explanation:

100/12=50/6=25/3=8.3333333...

1/3 of a foot is 1/3x12 which is 12/3 which is 4 in.

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4 years ago
PLEASE HELP! QUICK i'll give you brainliest if you answer correctly.
dem82 [27]

Answer:

8(-4) = -32

--32= 32

32 +4 =36

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3 years ago
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In 2007, the population of North America was approximately 5.15 x 10^8 people and the population of South America was approximat
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<span>C) 8.19 x 10^8 people </span>
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4 years ago
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Ponce Leon has a principal of $900 in his savings account on October 1. The money earns an APR of 6.5% calculated quarterly as s
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3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
3 years ago
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