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Otrada [13]
3 years ago
7

If roots of a quadratic equation are real and equal, then which of the

Mathematics
1 answer:
ycow [4]3 years ago
4 0

Answer: where are the options??

Step-by-step explanation:

You might be interested in
Find the volume and surface area of this prism.
mina [271]

Answer:

V = 408 cm cubed

SA = 558 cm squared

Step-by-step explanation:

To find the volume of a prism, multiply the area of the base by the height. This is 1/2 times width times height times length.

V =1/2 l*w*h =1/2* 6*8*17 = 408

To find the surface area of a prism, find the area of the triangular base and the area of each rectangular side.

Area of the base is A = 1/2 * b*h = 1/2 * 6 * 8 = 24. Since there are 2 bases, the area is 48.

Area of the rectangular side is A = b*h = 17*10 = 170. Since there are three, the area is 3*170 = 510.

The surface area of the prism is 48 + 510 = 558.

8 0
3 years ago
Which is a factor of each term of the polynomial?<br><br> (3d2 – 10d)
nydimaria [60]

Answer:

d(3d-10)

Step-by-step explanation:

You pull out the common factor of d from both terms, and group the remaining terms inside a parenthesis.

8 0
3 years ago
Determine the value of x
Tomtit [17]

Answer:

the answer will be Root 2

Step-by-step explanation:

x^2 = 1^2 + 1^2

We take the unmentioned side as 1 because it is an isosceles triangle and thus 2 of the sides will have the same measure

x^2 = 1 + 1

x^2 = 2

taking square root on both the sides

x = root of 2

3 0
3 years ago
The square of a number plus the original number is 22 what could the number be?
arlik [135]

Answer:

x²+22

Step-by-step explanation:

let the number= X

x²+22

7 0
3 years ago
Read 2 more answers
Applications 24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting h
SVEN [57.7K]

The given function is

h(x)=-16x^2+300x+20

According to this function, the starting height of the rocket is 20 feet because that's the initial condition of the problem stated by the independent term.

Additionally, we find the maximum height by calculating the vertex of the function V(h,k).

h=-\frac{b}{2a}

Where a = -16 and b = 300.

\begin{gathered} h=-\frac{300}{2(-16)}=\frac{300}{32}=\frac{150}{16}=\frac{75}{8} \\ h=9.375 \end{gathered}

Then, we find k by evaluating the function

\begin{gathered} k=-16(9.375)^2+300(9.375)+20 \\ k=-1406.25+2812.5+20=1426.25 \end{gathered}

Hence, the maximum height is 1426.25 feet.

At last, to know the time need to hit the ground, we just use h=9.375 and we multiply it by 2

t=2\cdot9.375=18.75

Hence, the rocket hits the ground after 18.75 seconds.

6 0
1 year ago
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