A newsletter publisher believes that more than 79% of their readers own a personal computer. Is there sufficient evidence at the
0.05 level to substantiate the publisher's claim? State the null and alternative hypotheses for the above scenario.
2 answers:
You might be interested in
A toy cost 0.85p in January.
Step-by-step explanation:
Given,
Mark down in January = 15%
Let,
Price in December = p
Mark down in January = 15% of price in December
Mark down in January =
Mark down in January = 0.15p
Price of toy in January = Price in December - Mark down
Price of toy in January = p - 0.15p = 0.85p
A toy cost 0.85p in January.
Keywords: mark down, subtraction
Learn more about subtraction at:
#LearnwithBrainly
Answer:
n = 61 costumers
Step-by-step explanation:
For calculating the number of costumers he should sample we use the next equation:
Where E is the error that we are prepared to accept, in this case E = 0.15
How we don't know the value of p, we can estimate it like p = 0.5
∝ = 1-0.98 = 0.02
1-∝/2 = 0.99
n = 60.32 costumers
n ≈ 61 costumers