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AnnZ [28]
3 years ago
8

A newsletter publisher believes that more than 79% of their readers own a personal computer. Is there sufficient evidence at the

0.05 level to substantiate the publisher's claim? State the null and alternative hypotheses for the above scenario.

Mathematics
2 answers:
Katarina [22]3 years ago
6 0

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

m_a_m_a [10]3 years ago
6 0

Answer:

Null hypothesis H0 : u = 0.79

Alternative hypothesis Ha : u > 0.79

Where u is the proportion of their readers that owns a personal computer.

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean.

While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

Therefore, for the case above;

Null hypothesis H0 : u = 0.79

Alternative hypothesis Ha : u > 0.79

Where u is the proportion of their reader that owns a personal computer.

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3 0
3 years ago
<img src="https://tex.z-dn.net/?f=1%2C%5Cfrac%7B1%7D%7B8%7D%2C%5Cfrac%7B1%7D%7B27%7D%2C%5Cfrac%7B1%7D%7B64%7D%2C...%2C%5Cfrac%7B
Alex
Answer: option C) 343

Justification:

The sequence of the denominators is:

term         denominator

1               1 = 1^3
2               8 = 2^3
3               27 = 3^3
4               64 = 4^3

5               5^3 = 125
6               6^3 = 216
7               7^3 = 343

And that is the term searched. So, the answer is the option C) 343.
5 0
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