All categories

3 years ago

Which graph represents (x,y)-pairs that make the equations y= 0.5x true?

Mathematics

1 answer:

tatyana61 [14]3 years ago

3 0

Answer:

Option C

Step-by-step explanation:

To find the corresponding graph substitute values of $x$ .

The graph is: $y = \frac{1}{2} x$ . Substitute $x = 2$ .

We get: $y = \frac{1}{2} (4) = 2$ . In the graphs only in Option C, $y = 2$ when $x = 4$ .

You might be interested in

Please help, i need to raise my grade

Dmitrij [34]

Answer:

$r=\dfrac{v^2}{a}$

Step-by-step explanation:

To isolate r, we're going to need to do some algebraic manipulation.

$a=\dfrac{v^2}{r}$

Multiply both sides by r:

$a\cdot r=v^2$

Divide both sides by a:

$r=\dfrac{v^2}{a}$

Hope this helps!

5 0

3 years ago

PEASE HELP! The table below shows the values of y for different values of x:

Shkiper50 [21]

<span>A) y = 3x because the slope (rate of change) is 3. The y-intercept is 0 so we don't necessarily need to add anything else.
</span>

4 0

3 years ago

Read 2 more answers

12x - 2y = -1<br>+ 4x + 6y= -4<br>

svp [43]

Answer:

x = -7/40 , y = -11/20

Step-by-step explanation:

Solve the following system:

{12 x - 2 y = -1 | (equation 1)

4 x + 6 y = -4 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{12 x - 2 y = -1 | (equation 1)

0 x+(20 y)/3 = (-11)/3 | (equation 2)

Multiply equation 2 by 3:

{12 x - 2 y = -1 | (equation 1)

0 x+20 y = -11 | (equation 2)

Divide equation 2 by 20:

{12 x - 2 y = -1 | (equation 1)

0 x+y = (-11)/20 | (equation 2)

Add 2 × (equation 2) to equation 1:

{12 x+0 y = (-21)/10 | (equation 1)

0 x+y = -11/20 | (equation 2)

Divide equation 1 by 12:

{x+0 y = (-7)/40 | (equation 1)

0 x+y = -11/20 | (equation 2)

Collect results:

Answer: {x = -7/40 , y = -11/20

6 0

3 years ago

four friends buy tickets for two shows on consecutive nights. They use a coupon for $5 off each ticket. They pay a total of $416

Serjik [45]

do u want the answer or how to solve it?

6 0

3 years ago

Read 2 more answers

Write the 10y1/2 in radical form

arsen [322]

It would just be the square root of 10y

so 10y under a radical. Assuming the y is to the power of 1/2

6 0

3 years ago