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allochka39001 [22]
4 years ago
10

central angle of a sector is 72° and the sector has an area of 16.2(pie) ft^2. what is the radius of the circle?

Mathematics
1 answer:
Cloud [144]4 years ago
6 0
Sector area = (central angle / 360) * PI * radius^2
sector area = (72 / 360) * PI * radius^2
radius^2 = sector area / [(72 / 360) * PI]
radius^2 = 16.2 * PI / [(1 / 5) * PI]
radius^2 = 16.2 / .2
radius^2 = 81
radius = 9

Source:
http://www.1728.org/radians.htm



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A two-way frequency table is shown below displaying the relationship between age and preferred cola beverage. We took a sample o
Mademuasel [1]

Answer:

60%

Step-by-step explanation:

The table with proper formatting is attached below.

We have to find the probability that a randomly selected person is 41-55 in age or prefers drinking Dr. Fizz.

Total number of people = 100

People in range 41 - 55 = 30

People who prefer Dr. Fizz = 30

People in range of 41 - 55 and prefer Dr. Fizz = 0

The general formula of probability in case of OR of two events is:

P ( A or B ) = P(A) + P(B) - P( A and B)

So for the given case we can write:

P (Person is in 41-55 range OR prefer Dr. Fizz) = P (Person is in 41 - 55 range) + P(Prefers Dr. Fizz) - P(Is in 41-55 range And prefers Dr. Fizz)

P (Person is in 41-55 range OR prefer Dr. Fizz) = 30/100 + 30/100 - 0/100

= 60/100

= 60%

Thus there is a 60% probability that a randomly selected person is 41-55 in age or prefers drinking Dr. Fizz

8 0
4 years ago
An object has a Mass of 5 kg what force is needed to accelerate it at 6/ms2
Ostrovityanka [42]

Answer:

Step-by-step explanation:

It can be solved by applying formula for Force.

Force = mass * acceleration

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one newton is the force applied on body when a body of mass one kg, accelerate at 1/ms^2 under the influence of force.

________________________

given

Mass = 5 kg

acceleration = 6/ms2

plug in the value of mass and acceleration in formula for for we have

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Thus 30 N(newton) force is required to accelerate at 6m/s^2

4 0
3 years ago
In the Reflecting Ball Game a ball can be launched from points 1, 2, 3, 4, 5 or 6 in the direction shown. When a ball hits a sid
natulia [17]

Answer:

24\sqrt{2}

Step-by-step explanation:

We can measure the number of diagonals each path takes:

From point 1, the path travels 6 diagonals, ending up at point D.

From point 2, the path travels 12 diagonals, ending back at point A.*

From point 3, the path travels 3 diagonals, ending at point B.

From point 4, the path travels 9 diagonals, ending at point C.

From point 6, the path travels 10 diagonals, ending at point D.

Since your question mentions each are 2 cm by 2 cm, this is equivalent to 2\sqrt{2}.

We can easily conclude that the maximum is 12 diagonals. Thus, Solving our equation gives: 12 * 2\sqrt{2}   = 24\sqrt{2} as our final answer.

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5 0
3 years ago
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