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Darya [45]
3 years ago
12

An alloy consists of nickel, zinc, and copper in the ratio 2:7:9. How many pounds of nickel have to be used to create alloy that

contains 4.9 lb of zinc?
Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0

We are given ratio nickel to zinc to copper = 2:7:9.

From this ratio we can see that <em>ratio of nickel to zinc is 2:7</em>.

Let us assume number of pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc is x pounds.

So, we can setup a proportion as :

x : 4.9 =  2:7

Or

\frac{x}{4.9}=\frac{2}{7}

On cross multiplication, we get

7x= 4.9× 2

7x = 9.8

Dividing both sides by 7, we get

x = 1.4.

<h3>Therefore, 1.4 pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc.</h3><h3 />
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The amount invested in each rate are $14500 and $12500 respectively;

Let the amount invested in each be P1 and P2

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If a total of $27,000 is invested, then;

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If the total interest after one year is $3385, then;

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\frac{P_1(12)(1)}{100} + \frac{P_2(13)(1)}{100}  = 3385\\0.12P_1+0.13P2=3385\\12P_1 + 13P_2=338500 ........................... 2

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12P1 + 12P12 = 324000

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12P2 - 13 P2 = 324000 - 338500

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P1 = 27000 - 14500

P1 = 12500

Hence the amount invested in each rate are $14500 and $12500 respectively;

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