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Darya [45]
3 years ago
12

An alloy consists of nickel, zinc, and copper in the ratio 2:7:9. How many pounds of nickel have to be used to create alloy that

contains 4.9 lb of zinc?
Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0

We are given ratio nickel to zinc to copper = 2:7:9.

From this ratio we can see that <em>ratio of nickel to zinc is 2:7</em>.

Let us assume number of pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc is x pounds.

So, we can setup a proportion as :

x : 4.9 =  2:7

Or

\frac{x}{4.9}=\frac{2}{7}

On cross multiplication, we get

7x= 4.9× 2

7x = 9.8

Dividing both sides by 7, we get

x = 1.4.

<h3>Therefore, 1.4 pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc.</h3><h3 />
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\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

Evaluate the expression 4(2x+y)-2y+z for x=-2, y=4 and z=-3

\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}

Before inserting the values of the variables, I recommend writing the equation in its simplest form.

First, use the distributive property and distribute 4:-

8x+4y-2y+z

Simplifying,

8x+2y+z

Now that the expression is in its simplest form, we can substitute the variables and simplify the expression.

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Final step:-

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-8-3

-11

<h3>Good luck.</h3>

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7 0
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Debra borrowed $8000 at a rate of 18% compounded semiannually. Assuming she makes no payment, how much will she owe after 9 year
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Answer:

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Hence She owe $37736.96 after 9 years .

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