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3 years ago

PLS GIMME ANSWER OR IM FAILING THIS

Mathematics

2 answers:

grin007 [14]3 years ago

8 0

The answer is 2/7 um there’s a word count thing on this so don’t mind the part

Sholpan [36]3 years ago

6 0

Answer:

2/7

Step-by-step explanation:

-1 1/7 + 6/7 = -8/7 + 6/7 = 2/7

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Paul wants to compare whether the prices of tangerines in two supermarkets differ significantly. He has been noting down the dai

masha68 [24]

We use the simple rules of statistics to accept the null hypothesis
68% of the data falls within 1 sd of the mean95% of the data falls within 2 sd of the mean 99% of the data falls within 3 sd of the mean
20 falls between the range of -56 to 56 (from the given 95% c.i.), hence we accept the null hypothesis; else, if the mean falls outside the range, we reject the null hypothesis.

6 0

3 years ago

Read 2 more answers

John, Joe, and James go fishing. At the end of the day, John comes to collect his third of the fish. However, there is one too m

Dmitry [639]

Answer:

The minimum possible initial amount of fish: $52$

Step-by-step explanation:

Let's start by saying that

$x$ = is the initial number of fishes

John:

When John arrives:

he throws away one fish from the bunch

$x-1$

divides the remaining fish into three.

$\dfrac{x-1}{3} + \dfrac{x-1}{3} + \dfrac{x-1}{3}$

takes a third for himself.

$\dfrac{x-1}{3} + \dfrac{x-1}{3}$

the remaining fish are expressed by the above expression. Let's call it John

$\text{John}=\dfrac{x-1}{3} + \dfrac{x-1}{3}$

and simplify it!

$\text{John}=\dfrac{2x}{3} - \dfrac{2}{3}$

When Joe arrives:

he throws away one fish from the remaining bunch

$\text{John} -1$

divides the remaining fish into three

$\dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3}$

takes a third for himself.

$\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}$

the remaining fish are expressed by the above expression. Let's call it Joe

$\text{Joe}=\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}$

and simiplify it

$\text{Joe}=\dfrac{2}{3}(\text{John}-1)$

since we've already expressed John in terms of x, we express the above expression in terms of x as well.

$\text{Joe}=\dfrac{2}{3}\left(\dfrac{2x}{3} - \dfrac{2}{3}-1\right)$

$\text{Joe}=\dfrac{4x}{9} - \dfrac{10}{9}$

When James arrives:

We're gonna do this one quickly, since its the same process all over again

$\text{James}=\dfrac{\text{Joe} -1}{3}+ \dfrac{\text{Joe} -1}{3}$

$\text{James}=\dfrac{2}{3}\left(\dfrac{4x}{9} - \dfrac{10}{9}-1\right)$

$\text{James}=\dfrac{8x}{27} - \dfrac{38}{27}$

This is the last remaining pile of fish.

We know that no fish was divided, so the remaining number cannot be a decimal number. We also know that this last pile was a multiple of 3 before a third was taken away by James.

Whatever the last remaining pile was (let's say $n$ ), a third is taken away by James. the remaining bunch would be $\frac{n}{3}+\frac{n}{3}$

hence we've expressed the last pile in terms of n as well. Since the above 'James' equation and this 'n' equation represent the same thing, we can equate them:

$\dfrac{n}{3}+\dfrac{n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}$

$\dfrac{2n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}$

L.H.S must be a Whole Number value and this can be found through trial and error. (Just check at which value of n does 2n/3 give a non-decimal value) (We've also established from before that n is a multiple a of 3, so only use values that are in the table of 3, e.g 3,6,9,12,..

at n = 21, we'll see that 2n/3 is a whole number = 14. (and since this is the value of n to give a whole number answer of 2n/3 we can safely say this is the least possible amount remaining in the pile)

$14=\dfrac{8x}{27} - \dfrac{38}{27}$

by solving this equation we'll have the value of x, which as we established at the start is the number of initial amount of fish!

$14=\dfrac{8x}{27} - \dfrac{38}{27}$

$x=52$

This is minimum possible amount of fish before John threw out the first fish

8 0

3 years ago

Cos(A) = ? 13/5 12/5 12/13 5/13

ollegr [7]

Answer:

cosA = $\frac{5}{13}$

Step-by-step explanation:

cosA = $\frac{adjacent}{hypotenuse}$ = $\frac{AC}{AB}$ = $\frac{5}{13}$

6 0

3 years ago

Andy, who loves to cook, makes apple cobbler for his family. The recipe (serves 6) calls for 5 3/4 pounds of apples, 6 3/4 cups

ch4aika [34]

Apples : 5 3/4 * 2 1/2 = 23/4 * 5/2 = 115/8 = 14 3/8 lbs

flour : 6 3/4 * 2 1/2 = 27/4 * 5/2 = 135/8 = 16 7/8 cups

margarine : 1/8 * 2 1/2 = 1/8 * 5/2 = 5/16 cups

sugar : 3 5/8 * 2 1/2 = 29/8 * 5/2 = 145/16 = 9 1/16 cups

cinnamon : 2 * 2 1/2 = 2/1 * 5/2 = 10/2 = 5 teaspoons

5 0

4 years ago

Read 2 more answers

3 3/8 divided by 3/4 using cross multiplication algorithm

Bogdan [553]

Answer

3 3/8 ÷ (3/4) = (9/2) = 4 ½

Explanation

We are asked to evaluate 3 3/8 divided by 3/4 using cross multiplication algorithm.

The algorithm will need us to put the mixed fraction in definite fraction form (improper fraction) and to evaluate the division, we change the division sign into multiplication sign and the fraction after the division sign changes into its reciprocal.

3 3/8 = (27/8)

(3 3/8) ÷ (3/4)

= (27/8) ÷ (3/4)

$\begin{gathered} \frac{27}{8}\div\frac{3}{4} \\ =\frac{27}{8}\times\frac{4}{3} \\ =\frac{108}{24} \\ \text{Divide numerator and denominator by 12} \\ \frac{108}{24}=\frac{9}{2} \end{gathered}$

Hope this Helps!!!

5 0

1 year ago