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Semmy [17]
3 years ago
10

To solve the equation 5sin(2x)=3cosx, you should rewrite it as___.​

Mathematics
2 answers:
statuscvo [17]3 years ago
6 0

Answer:

A. cosx(10sinx-3)=0

Step-by-step explanation:

5(2sinxcosx)=3cosx

10sinxcosx-3cosx=0

cosx(10sinx-3)=0

galina1969 [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

We want to solve the equation:

5\sin(2x)=3\cos(x)

To do so, we can rewrite the equation.

Recall the double-angle for sine:

\sin(2x)=2\sin(x)\cos(x)

By substitution:

5\left(2\sin(x)\cos(x)\right)=3\cos(x)

Distribute:

10\sin(x)\cos(x)=3\cos(x)

We can subtract 3cos(x) from both sides:

10\sin(x)\cos(x)-3\cos(x)=0

And factor:

\cos(x)\left(10\sin(x)-3\right)=0

Hence, our answer is A.

*It is important to note that we should not divide both sides by cos(x) to acquire 10sin(x) = 3. This is because we need to find the values of x, and one or more may result in cos(x) = 0, and we cannot divide by 0. Hence, we should subtract and then factor.

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