Question

On the graph of f(x)=cos x and the interval [0,2π), for what value of x does f(x) achieve a minimum?

Answer 1

Answer:

$cos(\pi)=-1$

Step-by-step explanation:

$f(x)=cos (x)$

State that the values where cos x is minimum:

$x=\pi +2\pi n, n\in \mathbb{Z}$

$cos(0)=1$

$cos\left(\frac{\pi}{4} \right)=\frac{\sqrt{2} }{2}$

$cos\left(\frac{\pi}{2} \right)=0$

$cos(\pi)=-1$

$cos\left(\frac{3\pi}{2} \right)=0$