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3 years ago

Can you solve for x pls

Mathematics

1 answer:

Ber [7]3 years ago

6 0

Answer:

x=11

Step-by-step explanation:

9x+6= 8X+17

X= 11

if my answer helps please mark as brainliest.

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Mathswatch Question! Mr Powers checks his electricity bill. Here are his meter readings. New reading: 6538 units, Old reading: 6

Setler79 [48]

Answer:

$Cost = 284 x$

Step-by-step explanation:

Given

$Old = 6245\ units$

$New = 6538\ units$

Required

The cost of units used

First, calculate the number of units used.

$Units = New - Old$

$Units = 6538 - 6254$

$Units = 284$

Next, multiply the units used by the cost per units,

Since the cost per unit is not given, we assume that it is x.

So, the total cost is:

$Cost = Units * Cost\ per\ units$

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3 0

3 years ago

Which equation(s) have x = –3 as the solution? log3(2x + 15) = 2 log5(8x + 9) = 2 log4(–20x + 4) = 3 logx81 = 4

baherus [9]

Answer:

log_3(2x+15)=2 and log_4(-20x+4)=3

Step-by-step explanation:

Plug it in and see!

$log_3(2x+15)=2\\log_3(2(-3)+15)=2\\log_3(-6+15)=2\\log_3(9)=2\\\text{ This is a true equation because } 3^2=9\\\\\\log_5(8(-3)+9)=2\\log_5(-24+9)=2\\log_5(-15)=2\\\\\text{ Not true because you cannot do log of a negative number }\\\\log_4(-20(-3)+4)=3\\log_4(64)=3\\\text{ this is true because } 4^3=64\\\\\\log_x (81)=4\\log_{-3}(81)=4\\\text{ the base cannot be negative }\\\\\\\\\text{ There is only two options here} \\\\log_3(2x+15)=2 \text{ and } log_4(-20x+4)=3$