Answer:
EF = 
≈ 5.83
Step-by-step explanation:
Calculate EF using the distance formula
d = 
with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)
EF = 
= 
= 
= ≈ 5.83 ( to 2 dec. places )
Answer:
Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.
Step-by-step explanation:
The volume of a hemisphere (
), measured in cubic centimetres, is obtained from this formula:
Where 
is the radius of the hemisphere, measured in centimetres.
We know that radius is the half of the diameter (
), measured in centimetres, then:
(
)
Now, we get the volume of each hemispherical bowl:
The total volume of six hemispherical bowl is:
From Physics we know that 1 litre equals 1000 cubic centimetres. Then:
Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.
Answer:
Step-by-step explanation:
<u>Given</u>
<u />
<u>Step 1: Combine Like Terms on LHS</u>
<u />
<u>Step 2: Subtract 11 on both sides</u>
<u />
<u>Step 3: Divide both sides by -4 to isolate the x-variable</u>
<u />
<u>Final Answer</u>
<u />
<span><span><span>10x</span>+8</span>=<span>−2</span></span>Step 1: Subtract 8 from both sides.<span><span><span><span>10x</span>+8</span>−8</span>=<span><span>−2</span>−8</span></span><span><span>10x</span>=<span>−10</span></span>Step 2: Divide both sides by 10.<span><span><span>10x</span>10</span>=<span><span>−10</span>10</span></span><span>x=<span>−<span>1</span></span></span>
Here's the rule for working with these things:
There are 3 signs associated with a fraction:
=> the sign of the numerator
=> the sign of the denominator
=> the sign of the whole fraction; (if the fraction were in
parentheses, this sign would be written outside).
-- You can change any 2 of them without changing the value of the fraction.
-- Changing any 1 of them changes the effective sign.
___________________________________
Now, you said the fraction is negative.
So, let's start with the positive fraction, and see the different ways
that we could make it a negative fraction:
=> mark only the numerator negative
=> mark only the denominator negative
=> put parentheses around the fraction, and mark it negative outside
If you do any one of these things to a normal positive fraction,
it turns into a negative fraction.
Look at the choices you listed in the question:
-- in the numerator only ? Yes. That makes it a negative fraction.
-- in the denominator only ? Yes. That makes it a negative fraction.
-- both ? No. That makes it the same as a positive fraction.
-- put parentheses around the fraction, and a negative sign outside ?
Yes. This makes it a negative fraction.
-- it doesn't matter ? No. I hope you can see that it does matter.
Have I confused you ?
Is this more than you wanted to know ?
