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mote1985 [20]
3 years ago
8

How do I graph y greater than equal to 5

Mathematics
1 answer:
Hatshy [7]3 years ago
7 0
On your graph, draw a horizontal line at y=5. Basically a line over (-3,5) to (3,5) or whatever the greatest x's are. Since it is greater than or equal to, it is a solid line. Greater than, you shade above the line
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During a sale a dress decreased in price from $80 to $76 what was the percent of decrease
Nesterboy [21]
<span>Well 68/80 as a percent is 85 % .I got that by dividing 68 by 80 and them multiplying by 100. 100-85= 15. So therefore the dress decreased in price by 15%. </span>
4 0
3 years ago
:
yuradex [85]

Answer:

B (1 , 3) , D (1 , -2)

Step-by-step explanation:

∵ A (-3 , 3) , C (-3 , -2)

∵ They have the same x-coordinate

∴ AC is a vertical segment its length = 3 - -2 = 5

∵ The area of the rectangle = 20

∴ The width of it = 20 ÷ 5 = 4

∴ x-coordinate of B: -3 + 4 = 1

∴ y-coordinate of B : 3 ⇒ AB horizontal segment

∴ B (1 , 3)

∵ x-coordinate of BD is 1 ⇒ BD is vertical segment

∵ y-coordinate = 3 - 5 = -2

∴ D (1 , -2)

3 0
3 years ago
Read 2 more answers
2 over 3 n =-12 what value of n makes the equation true?
galina1969 [7]

Answer:

-1/18

Step-by-step explanation:

4 0
3 years ago
Given two dice, what is the probability of rolling a four on the second die, given that you already rolled a four on the first d
Sholpan [36]

Answer:   1/6

Reason:

There's 1 side labeled "4" out of 6 sides total. So that's where the 1/6 comes from.

The "given that you already rolled a four on the first die" is unneeded info in my opinion, because each die is separate or independent from one another.

8 0
2 years ago
A bacteria culture begins with 15 bacteria which double in amount at the end of every hour. How many bacteria are grown during t
elixir [45]
We use P = i•e^rt for exponential population growth, where P = end population, i = initial population, r = rate, and t = time
P = 2•i = 2•15 = 30, so 30 = 15 [e^(r•1)],
or 30/15 = 2 = e^(r)
ln 2 = ln (e^r)
.693 = r•(ln e), ln e = 1, so r = .693
Now that we have our doubling rate of .693, we can use that r and our t as the 12th hour is t=11, because there are 11 more hours at the end of that first hour
So our initial population is again 15, and P = i•e^rt
P = 15•e^(.693×11) = 15•e^(7.624)
P = 15•2046.94 = 30,704
4 0
3 years ago
Read 2 more answers
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