There are 4 romantic novels and 6 adventurous novels on a book shelf. Without looking, Carmen chooses two novels out of the shel
f. What is the probability that she chooses 2 romantic novels?
It is NOT
It is NOT
1 answer:
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Answer:
x = 9.818
x≈10
The number of banners that can be made are 10
Step-by-step explanation:
We can use the knowledge of proportion to solve this.
First we need to convert yard to feet.
1 yard = 3 foot
4 1/2 yard = y
cross-multiply
y = 4 1/2 × 3
=9/2 × 3
y = feet
This implies 4 1/2 yards = feet
Let x be the numbers of banners needed to make from 4 1/2 yards of fabric.
1 3/8 feet = 1 banner
feets = x
cross multiply
1 3/8 × x =
=
cross-multiply
22x = 216
Divide both-side of the equation by 22
22x/22 = 216/22
x = 9.818
x≈10
The number of banners that can be made are 10
1. It's all about pattern matching, as a lot of math is.
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.
Realizing this, it should not be too much of a stretch to see
∠B ⇒ ∠K
∠C ⇒ ∠L
AC ⇒ JL
BC ⇒ KL
2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
1 ⇒ 1, so A ⇒ R
2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
ABCD ~ RQPS
3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.
Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.
Realizing this, it should not be too much of a stretch to see
∠B ⇒ ∠K
∠C ⇒ ∠L
AC ⇒ JL
BC ⇒ KL
2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
1 ⇒ 1, so A ⇒ R
2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
ABCD ~ RQPS
3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.
Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)