Answer:
T = 530N + 250
Step-by-step explanation:
For the first plan, Heather will deposit $250 and then save $135 per month.
So, that is 250 + (135 x N) where N is the number of months she saves the $135.
So if it is for 3months,
We will have:
t¹ = 135N + 250
= 250 + (135 x 3)
= 250 + 405
= $655
For the second plan, there is no initial deposit, but she will save $395 per month.
That is 395 x N
t² = 395N
For 3months, we have 395 x 3 = $1185
Therefore the total for both plans in 3months = 655 + 1185 = $1840
Equation relating T to N
T = t¹ + t²
T = (135N + 250) + 395N
T = 135N + 250 + 395N
T = 530N + 250
(X+1) y (2x-1) this is the answer
Answer:I would do the same thing which is copy and paste because its very
difficult to find out how to do it but ill keep trying
Step-by-step explanation:
Answer:

Step-by-step explanation:
Let's re-write the equations in order to get the variables as separated in independent terms as possible \:
First equation:

Second equation:

Third equation:

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

Now we use this value for "x" back in equation 1 to solve for "y":

And finally we solve for the third unknown "z":

Let's represent the number of hours with the variable 'h' (or whatever letter you want it to be):
265 + 48h = 553
Substract both sides by 265:
48h = 288
Divide:
h = 6
6 hours of labor was spent