Answer:
In algebraic terms this means x-17>33
Step-by-step explanation:
to solve it x−17>33
1 Add 17 to both sides.
x>33+17
2 Simplify 33+17 to 50
x>50
The answer is 14.60. Hope this helps!
Answer:
Step-by-step explanation:
The graph shows the solution (-6,2)
i.e at x= -6 y=2
Analysis of each of the answers, since we can't write the equation of a straight line with only that information i.e the single point
Then,
Option 1
1. 2x - 3y = -6
x= -6 y=2
Then let insert x=-6 and y =2
2(-6)-3(2)
-12-6
-18.
Since -18 ≠ -6, then this is not the equation of the line and doesn't make up the system
Option 2
2. 4x - y = 26
Inserting x=-6 and y=2
4(-6)-(2)
-24-2
-26
Since -26 ≠ 26, then this is not the equation of the line and doesn't make up the system
Option 3
3. 3x + 2y = -14
Inserting x=-6 and y=2
3(-6)+2(2)
-18+4
-14
Since -14 ≠ -14 then this is the equation of the line and it make up the system.
Option 4
x-y = -2
Inserting x=-6 and y=2
(-6)-(2)
-6-2
-8
Since -8≠ -2, then this is not the equation of the line and doesn't make up the system
Option 5
5. x+y=-4
Inserting x=-6 and y=2
(-6)+(2)
-6+2
-4
Since -4 ≠ -4, then this is the equation of the line and it makes up the system.
Then, there are two option that make up the system
3. 3x + 2y = -14
And
5. x+y=-4
Answer:
5/28
Step-by-step explanation:
1/1 represents the whole amount of tickets.
4/7 are sold on Thursday.
an additional 1/4 are did on Friday.
fraction of available tickets on Saturday are therefore
1/1 - 4/7 - 1/4 = 4/1 - 16/7 - 1/1 = 28/1 - 16/1 - 7/1 = 5/1
that means out of 28 equal parts of the total number of tickets 16+7 = 23 parts have been sold.
so, there are only 5 out of the total 28 parts available on Saturday, and the fraction of available tickets is therefore 5/28.
we could have also tried to bring both fractions to the same denominator, and found that this is 28.
and then
4/7 + 1/4 = 4/4 × 4/7 + 7/7 × 1/4 =
= 16/28 + 7/28 = 23/28
and the whole is 28/28.
so we have 28/27 - 23/28 = 5/28 left.
surprise, surprise, it is the same result ...
Answer:
Is this a question or..........
Step-by-step explanation:
