Answer:
-10
-5
5
Step-by-step explanation:
From the answers given, you probably mean f(x) = x^3 + 10x2 – 25x – 250
The Remainder Theorem is going to take a bit to solve.
You have to try the factors of 250. One way to make your life a lot easier is to graph the equation. That will give you the roots.
The graph appears below. Since the y intercept is -250 the graph goes down quite a bit and if you show the y intercept then it will not be easy to see the roots.
However just to get the roots, the graph shows that
x = -10
x = - 5
x = 5
The last answer is the right one. To use the remainder theorem, you could show none of the answers will give 0s except the last one. For example, the second one will give
f((10) = 10^3 + 10*10^2 - 25*10 - 250
f(10) = 1000 + 1000 - 250 - 250
f(10) = 2000 - 500
f(10) = 1500 which is not 0.
==================
f(1) = (1)^3 + 10*(1)^2 - 25(1) - 250
f(1) = 1 + 10 - 25 - 250
f(1) = -264 which again is not zero
Answer:
7/10 and 7/8 are both less than 1.
Step-by-step explanation:
The product must be less than either factor because when you multiply a number by less than 1, the number gets smaller.

- Given - <u>a </u><u>rectangle </u><u>with </u><u>length</u><u> </u><u>2</u><u>5</u><u> </u><u>feet </u><u>and </u><u>perimeter </u><u>8</u><u>0</u><u> </u><u>feet</u>
- To calculate - <u>width </u><u>of </u><u>the </u><u>rectangle</u>
We know that ,

where <u>b </u><u>=</u><u> </u><u>width </u><u>/</u><u> </u><u>breadth</u> of rectangle
<u>substituting</u><u> </u><u>the </u><u>values </u><u>in </u><u>the </u><u>formula </u><u>stated </u><u>above </u><u>,</u>

hope helpful ~
Answer: see Explanation
Step-by-step explanation:
THE GAINEY'S:
Recursive Formula :
A1 = $10
An = An-1 + $10
A2 = $10 + $10 = $20
Where n = day of the month
Explicit formula :
y = a + b(c - 1)
WHERE:
y = final amount
initial amount = a
Increment on initial amount = b
Day of the month = c
THE ARNOLD'S :
Recursive formula:
First day of the month (A1) = $10
An = 2(An-1)
A2 = 2(A1) = 2(10) = $20
A3 = 2(A2) = 2(20) =$40
Explicit formula:
y = a(b)^c
Where :
y = final amount
initial amount = a
Increment on initial amount = b
Day of the month = c