Point slope form = y - y1 = m (x - x1)
y - 5 = -1 (x -(-1))
y - 5 = -1 (x+1)
Hope this helps :)
option D is correct answer.
Y = 5/2 x + 2
2 y = 5 x + 4 ( we will use the substitution method )
2 ( 5/2 x + 2 ) = 5 x + 4
5 x + 4 = 5 x + 4
0 · x = 0
x , y ∈ R
Answer : C ) infinitely many solutions.
Given that the range of the signal is a quadratic function:
(x-h)^2 = 4a (y - k)
(5-4)^2 = 4a (4 - 2)
4a =1/2 therefore,
(x -4)^2 = (1/2)(y – 2)
The road is a line.
Slope of the road is (7 -2)/(-3 -8) =-5/11
Therefore the equation of the line:
5x + 11y = 5(8) + 11(2)
5x + 11y = 62
9514 1404 393
Answer:
(x, y) = (-2.5, -4)
Step-by-step explanation:
Since you are given an expression for y, it is convenient to substitute that into the second equation.
2x -3(6x +11) = 7
2x -18x -33 = 7
-16x = 40 . . . . . . add 33
x = -40/16 = -2.5
Using the equation for y, we find ...
y = 6(-2.5) +11 = -15 +11 = -4
The solution is (x, y) = (-2.5, -4).