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xxMikexx [17]
3 years ago
15

Need help please ty (: Find x.

Mathematics
2 answers:
MArishka [77]3 years ago
8 0
<h3>Answer:  x = 18 (choice B)</h3>

===================================

Work Shown:

Through the inscribed angle theorem, we can say that 2 times the inscribed angle gets us the arc that the inscribed angle cuts off.

2*(inscribed angle) = arc measure

2*(2x+2) = 76

4x+4 = 76

4x+4-4 = 76-4 ... subtract 4 from both sides

4x = 72

4x/4 = 72/4 ... divide both sides by 4

x = 18

PSYCHO15rus [73]3 years ago
3 0

Answer:

Step-by-step explanation:

2 × inscribed angle = 76

2 × (2x + 2) = 76

Open bracket

4x + 4 = 76

Collect like terms

4x = 76 - 4

4x = 72

Divide both sides by 4

4x/4 = 72/4

X = 18

Therefore X is Equal to 18.

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Evaluate the expression <br> |2x-8|<br><br> X=2
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4

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¿cuáles son los criterios de congruencia y semejanza de triángulo?
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Two triangles are similar if they meet one of the following criteria. : Two pairs of corresponding angles are equal. : Three pairs of corresponding sides are proportional. : Two pairs of corresponding sides are proportional and the corresponding angles between them are equal.

Dos triángulos son similares si cumplen uno de los siguientes criterios. : Dos pares de ángulos correspondientes son iguales. : Tres pares de lados correspondientes son proporcionales. : Dos pares de lados correspondientes son proporcionales y los ángulos correspondientes entre ellos son iguales.

Step-by-step explanation:

3 0
3 years ago
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A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/
xz_007 [3.2K]

Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016

The degrees of freedom for this sample size are:

df=n-1=25-1=24

The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.318 \cdot 0.016=0.021

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186

The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).

6 0
3 years ago
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