Answer with Step-by-step explanation:
We are given that
and
are linearly independent.
By definition of linear independent there exits three scalar
and
such that

Where 

We have to prove that
and
are linearly independent.
Let
and
such that





...(1)

..(2)

..(3)
Because
and
are linearly independent.
From equation (1) and (3)
...(4)
Adding equation (2) and (4)


From equation (1) and (2)

Hence,
and
area linearly independent.
Answer:
31/5
Step-by-step explanation:
[f(4) - f(-1)] / 4-(-1)
Let the two numbers be x and y.
Let m = the fraction (or percentage) for increasing the numbers.
Increase x by 5, multiply (x+5) by (1+m), and set it qual to 36.
(x + 5)*(1 + m) = 36
Increase y by 5, multiply (y+5) by (1+m), and set it equal to 36.
(y+5)*(1+m) = 36
Therefore
(x+5)*(1+m) = (y+5)*(1+m)
x + 5 = y + 5
x = y
x - y = 0
Answer: 0.
The difference between the two numbers is zero.