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KonstantinChe [14]
3 years ago
15

Find the length of A? Anyone know?....

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0
A² = b² + c² - 2bcCos A
a² = 11² + 13² - 2(11)(13)Cos(108)
a² = 378.38
a = √378.38
a = 19.45

Answer: 19.45
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

In the given figure, the Angle (6v - 4)° forms vertical opposite angle pair with 50° , so their measures is equal to one another.

that is :

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mel-nik [20]

Answer:

Correct option is

B

0

D

−1

sinx+sin2x+sin3x

=sin(2x−x)+sin2x+sin(2x+x)

=2sin2xcosx+sin2x [ by using sin(A+B)=sinAcosB+sinBcosA and sin(A−B)=sinAcosB−sinBcosA ]

=sin2x(2cosx+1)........(i)

cosx+cos2x+cos3x

=cos(2x−x)+cos2x+cos(2x+x)

=2cos2xcosx+cos2x [By using cos(a−b)=cosa⋅cosb+sina⋅sinb and cos(a+b)=cosa⋅cosb−sina⋅sinb]

=cos2x(2cosx+1).....(ii)

∴(sinx+sin2x+sin3x)

2

+(cosx+cos2x+cos3x)

2

=1

sin

2

2x(2cosx+1)

2

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2

2x(2cosx+1)

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⇒(2cosx+1)

2

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⇒2cosx+1=±1

∴cosx=0or−1

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