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KonstantinChe [14]
3 years ago
15

Find the length of A? Anyone know?....

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0
A² = b² + c² - 2bcCos A
a² = 11² + 13² - 2(11)(13)Cos(108)
a² = 378.38
a = √378.38
a = 19.45

Answer: 19.45
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At a movie theater adult tickets cost $10, and child tickets cost $6. Which equation can be
Shkiper50 [21]

Answer:  Choice A

s = 10k + 6(5)

========================================================

Reason:

k = number of adults

10k = cost for all the adults (at $10 per ticket)

5 = number of children

6(5) = cost for all the children ($6 per ticket)

10k + 6(5) = total cost for all adults and children

s = total cost in dollars

s = 10k+6(5)

4 0
2 years ago
What is the sum of the interior angles of the polygon pictured below?
kkurt [141]

3420°

explanation:

the equation of the sum of interior angles are (n-2)x180

polygon above has 21 sides so you sub n as 21 and plug the equation in the calculator

8 0
3 years ago
Read 2 more answers
A random sample is selected from a population with mean μ = 102 and standard deviation σ = 10. For which of the sample sizes wou
chubhunter [2.5K]

Answer:

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

Step-by-step explanation:

For this case we know that for a random variable X we have the following parameters given:

\mu = 102, \sigma =10

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

8 0
3 years ago
Each cement block weighs 1 1/4 how much do 8 cement blocks weigh
vladimir1956 [14]

Answer:

10

Step-by-step explanation:

(1 1/4) * 8 = 10

3 0
3 years ago
Helppppppp!<br><br> Right quick
Nesterboy [21]

Answer:

LN = 5x + 9

Step-by-step explanation:

LN = x + 9 + 4x

LN = 5x + 9

4 0
3 years ago
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