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Viktor [21]
4 years ago
6

Thea and Eleanor are reading the same book. The graph shows the number of words Thea. The graph shows the number of words Thea r

eads over time. Elinor reach 225 words per minute
Mathematics
1 answer:
nadya68 [22]4 years ago
5 0

The answers are:

Thea reads 180 words per minute.

Eleanor reads 450 words every 2 minutes.

After 1 hour of reading, Eleanor reads more words than Thea.

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Answer:

Adjacent

Step-by-step explanation:

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3 years ago
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Inessa05 [86]
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3 years ago
In a chemical plant, 24 holding tanks are used for final product storage. Suppose that six of the tanks contain high viscosity m
andriy [413]

Answer:

The probability is 0.461

Step-by-step explanation:

Since six tanks contain high viscosity material, it means that 18 does not contain since the total number of tanks is 24.

Now, here, we know that we are selecting a total of 4 tanks.

out of the tanks with high viscosity materials, we will be selecting one only while out of the others without viscosity materials we shall need selecting three.

Thus,

the number of ways we can select one tank with viscosity material from a total of six tanks will be 6C1 = 6 ways

Now, we want to select three from the remaining 18 tanks

The number of ways we can do this is 18C3 = 816 ways

Finally, we are selecting 4 out of 24 tanks.

The number of ways we can do this is 24C4 = 10,626 ways

Now, we proceed to calculate the probability.

Kindly note that we are selecting 1 from 4 and 3 from 18

The term ‘and’ in probability means we are multiplying the probabilities of these events together and thus, that means that we are going to combine our numbers of selections.

So the total number of ways in which we can select 1 out of 3 and 3 out of 18 will be = 6 * 816 = 4,896 ways

The probability would now be 4896/10626 = 0.461

5 0
4 years ago
In the diagram below lines p and r are parallel. Line s is a Transversal that is not perpendicular to lines p and r
malfutka [58]

Answer: Any of the following angles are <u>not</u> congruent to angle 5.

  • angle 2
  • angle 4
  • angle 6
  • angle 8

The only exception being that if angle 5 is 90 degrees, then so are the remaining four angles shown above (in fact, all 8 angles are right angles).

========================================================

Explanation:

Angles 2 and 5 are supplementary since line p is parallel to line r. This means angle 2 and angle 5 add to 180 degrees. The two angles are only congruent if both are right angles (aka 90 degree angles); otherwise, they are not congruent angles.

Angle 2 = angle 4 because they are vertical angles. So because these two angles are congruent, and angle 2 does not have the same measure as angle 5, this consequently leads to angle 4 also not being the same measure as angle 5 (unless both are right angles).

Angle 2 = angle 8 because they are alternate interior angles. Following the same logic path as the last paragraph, we see that angles 8 and angle 5 aren't the same measure. Or we could note that angle 5 and angle 8 form a straight angle, so they must add to 180 degrees. The two angles are only congruent if they were 90 degrees each, or otherwise not congruent at all.

Similar logic can also show that angle 6 is not congruent to angle 5.

---------------------------

An alternative path is to find all the angles that are always congruent to angle 5 and they are...

  • angle 1 (corresponding angles)
  • angle 3 (alternate interior angles)
  • angle 7 (vertical angles)

And everything else is not congruent to angle 5.

6 0
3 years ago
Complete the data table for the function f(x) = -x - 2 + 2.
alexgriva [62]

Given the following function:

\text{ f(x) = }\sqrt[]{-x\text{ -2}}\text{ + 2}

y = f(x)

Therefore, let's complete the data table by substituting each x-values to be able to get the respective y-values,

We get,

At x = -2,

\text{ y = f(x) = }\sqrt[]{-x-2}\text{ + 2}\text{f(-2) = }\sqrt[]{-(-2)-2}\text{ + 2}\text{ = }\sqrt[]{2\text{ - 2}}\text{ + 2}\text{ = }\sqrt[]{0}\text{ + 2}\text{ y = f(-2) = 2}

Therefore, y = 2 at x = -2.

At x = -3,

\text{ y = f(x) = }\sqrt[]{-x-2}\text{ + 2}\text{f(-3) = }\sqrt[]{-(-3)-2}\text{ + 2}\text{= }\sqrt[]{3-2}\text{ + 2}\text{= }\sqrt[]{1}\text{ + 2}\text{= }1\text{ + 2}\text{ f(-3) = 3}

Therefore, y = 3 at x = -3.

At x = -6,

8 0
1 year ago
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