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Misha Larkins [42]
2 years ago
14

1+sinx+cosx/1+sinx-cosx=1+cosx/sinx help pls by proving

Mathematics
1 answer:
Monica [59]2 years ago
6 0

Answer:

Below.

Step-by-step explanation:

I'll  write sin x as s and cos x as c so we have:

(1 + s +c)/(1 + s - c) = (1 + c)/s

Cross multiplying:

s + s^2 + cs  = 1 + s - c + c + cs - c^2

s  + s^2 + cs = 1 + s + cs - c^2

s^2 + c^2 + s - s + cs - cs = 1

s^2 + c^2 = 1.

- that is sin^2 x + cos^2 x = 1 which is a known identity.

Therefore the original identity is proved.

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How would the function change if the base of the exponent were between 0 and 1? If the base of the exponent were 1, the function would remain constant. The graph would be a horizontal line. If the base of the exponent were less than 1, but greater than 0, the function would be decreasing.

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emmainna [20.7K]

Based on the multiplication property of equality, the statement that completes the proof is: C. CD = b(sin A) and CD = a(sin B).

<h3>What is the Multiplication Property of Equality?</h3>

The multiplication property of equality is given as, if a/b = y, then a = yb. Both sides of the equation is multiplied by the same value.

In step 5 where the multiplication property of equality is applied, we would have:

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This same property is applied to sin B = CD/a to get CD = a(sin B).

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Learn more about the multiplication property of equality on:

brainly.com/question/1978763

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