Let a,b,c,d and e are five numbers
mean = (a +b+ c+ d+e)/5 = 30
⇒ (a +b+ c+ d+e) = 150_______(1)
now, Let the number excluded be a
then, new mean = (b+ c+ d+e)/4 = 28
⇒ (b+ c+ d+e)= 112
putting this value in (1),
⇒a + 112 = 150
⇒a = 150 -112 = 38
excluded number = 38
What do you need to help?
Answer:
57 and 12
Step-by-step explanation:
To find that you would do (such that x is the unknown) 3x+5(x+2)=106
and if you do this you will find that x=12
so the two numbers you are looking for are 12 and 14
I believe you set them equal to each other.
2x+4=5x-9
x=4.3
2(4.3)+4=12.6
I think the answer is 12.6
