Answer:
D) both groups are equatorial.
Explanation:
To solve this question we can start by drawing the molecule in using the <u>structure of the hexagon</u>. In this structure, we have the methyl group on carbon 1 and the terbutyl group on carbon 3, additionally, if we have a cis structure both groups must have the same type of bond (in this case the wedge bond). (See figure 1)
When we write the <u>chair structure</u>, we must keep the same structure. That is, methyl must be on carbon 1 and terbutyl on carbon 3. Also, the cis configuration must be maintained. With this in mind, we can choose the <u>equatorial configuration</u> for methyl on carbon 1 (since the position equatorial is the one that has <u>less steric impediment and more stability</u>). If this is true for carbon 1, we must place the terbutyl group on carbon 3 in the same configuration (i.e. cis). Therefore, on carbon 3 we must place the tert-butyl down on carbon 3, that is, in the <u>equatorial position</u>. (See figure 1).
Therefore, in the chair-like structure, both groups must be in an equatorial position.
I hope it helps!
1 it a 2 it b 3 it c 4 it be 7 it a
<h3>Answer:</h3>
[OH⁻] = 1.0 × 10⁻¹⁰ M
<h3>Solution:</h3>
In order to calculate concentration of hydroxide ion i.e. [OH⁻] first we will find the pOH by using following relation,
pH + pOH = 14
Putting value of pH given and solving for pOH,
4.0 + pOH = 14
pOH = 14 - 4.0
pOH = 10.0
As ,
pOH = -log [OH⁻]
So,
[OH⁻] = 10^-pOH
Putting value of pOH,
[OH⁻] = 10⁻¹⁰
[OH⁻] = 1.0 × 10⁻¹⁰ M
Average atomic mass is the weighted average atomic mass of an element with regard to the abundance of all its isotopes.
average atomic mass of X can be calculates as follows;
average atomic mass of X = sum of the products of mass of isotopes by their abundance percentages
average atomic mass of X = (94.93 % x 31.97207 amu) + (0.7640% x 32.97146 amu) + (4.290% x 33.96786 amu) + (1.600×10−2% x <span>35.96709 amu)
</span>average atomic mass of X = 30.35 + 0.2519 + 1.457 + 0.005755
therefore average atomic mass of X = 32.06