How much energy is released if a sample loses 0.05 kg mass through radioactive decay?

Sort the compounds: conjugated or non conjugated. -but-2-enoic acid -butanoic acid -hex-4-en-3-one -hexan-3-one

Oliga [24]

By definition of conjugated and non-conjugated acids, Conjugate acids are a type of acid that gains a proton in solution in response to a base that has happily accepted a proton.

This how the compounds are to be sorted.
-butanoic acid
-but-2-enoic acid
-hexan-3-one
-hex-4-en-3-one

3 0

4 years ago

Read 2 more answers

Suppose that a person eats a diet of 2391 Calories per day.a.) Convert this energy into J. Express your answer using four signif

alekssr [168]

Explanation:

(a)

The given data is:-

Energy = 2391 Calories

The conversion of calories to J is shown below as:-

1 calorie = 4.184 J

So,

Energy = 4.184 * 2391 J = 10003.944 J

Answer in four significant digits: - $1.000\times 10^4\ J$

(b)

The conversion of calories to kJ is shown below as:-

1 calorie = 0.004184 kJ

So,

Energy = 0.004184 * 2391 kJ = 10.003944 kJ

Answer in four significant digits: - $1.000\times 10\ kJ$

(c)

The conversion of calories to kWh is shown below as:-

1 calorie = $1.1622\times 10^{-6}$ kWh

So,

Energy = $1.1622\times 10^{-6}\times 2391$ kWh = 0.002778873 kWh

Answer in four significant digits: - $0.002779\ kWh$

8 0

4 years ago

What volume of 1.00 m hcl in liters is needed to react completely (with nothing left over) with 0.750 l of 0.100 m na2co3?

kotykmax [81]

The balanced equation for the reaction is as follows
Na₂CO₃ + 2HCl --> 2NaCl + CO₂ + H₂O
stoichiometry of Na₂CO₃ to HCl is 1:2
number of Na₂CO₃ moles reacted = molarity x volume
number of Na₂CO₃ moles = 0.100 mol/L x 0.750 L = 0.0750 mol
according to molar ratio of 1:2
1 mol of Na₂CO₃ reacts with 2 mol of HCl
then 0.0750 mol of Na₂CO₃ mol reacts with - 2 x 0.0750 = 0.150 mol
molarity of given HCl solution is 1.00 mol/L
molarity is defined as the number of moles of solute in 1 L of solution
there are 1.00 mol in 1 L of solution
therefore there are 0.150 mol in - 0.150 mol / 1.00 mol/L = 0.150 L
volume of HCl required is 0.150 L

3 0

3 years ago

Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits and put the units.

marta [7]

Answer:

Approximately $53.3\; \rm g$ .

Explanation:

Lookup Avogadro's Number: $N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1}$ (three significant figures.)

Lookup the relative atomic mass of $\rm H$ , $\rm S$ , and $\rm O$ on a modern periodic table:

$\rm H$ : $1.008$ .
$\rm S$ : $32.06$ .
$\rm O$ : $15.999$ .

(For example, the relative atomic mass of $\rm H$ is $1.008$ means that the mass of one mole of $\rm H\!$ atoms would be approximately $1.008\!$ grams on average.)

The question counted the number of $\rm H_2SO_4$ molecules without using any unit. Avogadro's Number $N_{\rm A}$ helps convert the unit of that count to moles.

Each mole of $\rm H_2SO_4$ molecules includes exactly $(1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23}$ of these $\rm H_2SO_4 \!$ molecules.

$3.27 \times 10^{23}$ $\rm H_2SO_4$ molecules would correspond to $\displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol$ of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of $\rm H_2SO_4$ gives the mass of each mole of $\rm H_2SO_4\!$ molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

$\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}$ .