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3 years ago

A number that when substituted for the variable makes a true statement

Mathematics

1 answer:

Elza [17]3 years ago

3 0

Your answer should be: a solution

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What is the factored form of the expression. (2n^2 + 5n + 3) (4n - 5)

7nadin3 [17]

So firstly, the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.

So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:

$(2n^2 + 2n + 3n + 3)(4n - 5)$

Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:

$(2n(n+1)+3(n+1))(4n-5)$

Now we can rewrite this expression as $(2n+3)(n+1)(4n-5)$ , which is your final answer.

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3 years ago

Find the GCF. 12 and 45 A. 180 B. 3 C. 45 D. 12

marin [14]

The greatest common factor that twelve & forty-five share is three.

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3 years ago

What is the nearest whole number rounded to 67400

viktelen [127]

67401 or 67400 or 67399

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3 years ago

What do you start with? 6(3+8n)=210

neonofarm [45]

Always start with what’s in the parentheses:)

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3 years ago

Read 2 more answers

What are the chances your flight will leave on time? Below are a histogram and summary statistics for the percentage of flights

Jet001 [13]

Answer:

80.0456< $\bar x$ <81.1210

Step-by-step explanation:

-Given the mean, $\bar y=80.5833$ and $s=2.77369$ , the confidence interval can be calculated using the formula:

$\bar x\pm z\times \frac{\sigma}{\sqrt{n}}$

#We substitute our values in the formula to solve for CI:

$=\bar x\pm z\times \frac{\sigma}{\sqrt{n}}\\\\=\bar y\pm z_{0.05}\times \frac{s}{\sqrt{72}}\\\\=80.5833\pm 1.645\times \frac{2.77369}{\sqrt{72}}\\\\=80.5833\pm0.5377\\\\=[80.0456,81.1210]$

Hence, the confidence interval lies between 80.0456 and 81.1210

4 0

3 years ago