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2 years ago

If I have a 40 % and my teacher puts in 3 100% what’s my grade ?

Mathematics

2 answers:

Black_prince [1.1K]2 years ago

6 0

It would be an A if i'm correct.

aliya0001 [1]2 years ago

6 0

Your grade would be an 85%. The way you do the math is to add the 3 100% together to get 300%. Then you would add the 40% to the 300% to get 340%. After, you would divide that percentage by four since you added only four numbers. When you divided, you would get 85%.

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Tcecarenko [31]

Answer:

x = 4

Step-by-step explanation:

To solve, simplify the expression then use inverse operations to isolate x.

$x - 4 = 0^2\\x-4 = 0\\x-4+4=0+4\\x = 4$

7 0

3 years ago

San R APOR is a right triangle. IF RO = 8, what is PO? mios 16

attashe74 [19]

Answer:

PQ = 16

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos60° = $\frac{1}{2}$ , then

cos60° = $\frac{adjacent}{hypotenuse}$ = $\frac{RQ}{PQ}$ = $\frac{8}{PQ}$ = $\frac{1}{2}$ ( cross- multiply )

PQ = 8 × 2 = 16

6 0

2 years ago

Solve for the m in the equation

velikii [3]

Answer:

$m = 15$

Step-by-step explanation:

$\frac{m}{9 } + \frac{2}{3} = \frac{7}{3}$

Multiply both sides of the equation by 99, the least common multiple of 9,39,3.

m + 6 =21

Subtract 6 from both sides.

m = 21 - 6

Subtract 6 from 21 to get 15.

m=15

5 0

3 years ago

A can do a piece of work in 4 hours and B can do it in 6 hours. How much time would they take working together to finish the wor

Kipish [7]

Answer:

2.4 hours

Step-by-step explanation:

Let total work = X

Rate of work done = X ÷ time

Rate of A = X/4

Rate of B = X/6

If they work together, rate is the sum of their individual rates, i.e.

X/4 + X/6

= (3X + 2X)/12 (taking LCM)

=5X/12

Rate = X/time

5X/12 = X/time

time = X÷(5X/12)

time = X × 12/(5X)

time = 2.4 hours

Shortcut:

Product of individual times/sum of individual times

= (4×6)/(4+6)

=24/10

=2.4 hours

8 0

3 years ago

Read 2 more answers

West high schools population is 250 students fewer then twice the population of East High school the two schools have a total of

gizmo_the_mogwai [7]

Answer:

1036 students

Step-by-step explanation:

Let the number of students at West High be "w" and the number of students at East High be "e"

West High population is 250 FEWER than TWICE of East High, we can write:

w = 2e - 250

Total students in both schools is 2858, so we can write 2nd equation as:

e + w = 2858

We can replace 1st equation in 2nd to get an equation in e, and find "e":

e + w = 2858

e + (2e - 250) = 2858

3e - 250 = 2858

3e = 2858 + 250

3e = 3108

e = 3108/3

e = 1036

Hence,

number of students attending East High School = 1036 students

3 0

2 years ago