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3 years ago

What is ansewer 1/6 of 30

Mathematics

2 answers:

pochemuha3 years ago

8 0

Answer:

Step-by-step explanation:

sergey [27]3 years ago

5 0

The right answer is 5.

look at the attached picture

Hope it helps...

Good luck on your assignment

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What is the slope and y intercept of the following linear equation:y=1/3×-2

gulaghasi [49]

Answer:

Step-by-step explanation:

The general formula for slope-intercept form is y = mx + b

We can see that m (slope) equals 1/3 here. We can also see that the y-intercept (b) is -2. Another way to find the y intercept is to make x equal to 0. You get 0 - 2 which equals -2

Note:

If youre ever asked for the x-intercept, make y equal to zero and solve for x.

5 0

3 years ago

2x^3y + 18xy - 10x^2y - 90y part b: rewrite the expression completely factored.

pogonyaev

Answer:

Part A: Factor out the GCF. In this case, the GCF is 2y. So it looks like

2 x^3 * y+18xy-10 x^2 * y-90y=2y (x^3 - 5 x^2 + 9x-45)

Part B: The result from above will need to be factored by grouping.

Part C: If you switch the terms, the factoring will work out differently, but at the end, the factorization will be the same.

Step-by-step explanation:

8 0

3 years ago

Problem:

valkas [14]

Answer:

Part B. see the procedure

Part C. see the procedure

Step-by-step explanation:

we have

$f(x)=x^{2}+2x+1$ -----> equation A

$g(x)=3-x-x^{2}$ -----> equation B

Part B. Solve the system algebraically

equate the equation A and the equation B

$x^{2}+2x+1=3-x-x^{2}$

$2x^{2}+3x-2=0$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^{2}+3x-2=0$

$a=2\\b=3\\c=-2$

substitute in the formula

$x=\frac{-3(+/-)\sqrt{3^{2}-4a(2)(-2)}} {2(2)}$

$x=\frac{-3(+/-)\sqrt{25}} {4}$

$x=\frac{-3(+/-)5} {4}$

$x1=\frac{-3(+)5} {4}=0.5$

$x2=\frac{-3(-)5} {4}=-2$

Find the values of y

For x=0.5

$f(0.5)=0.5^{2}+2(0.5)+1=2.25$

For x=-2

$f(-2)=(-2)^{2}+2(-2)+1=1$

the solutions are the points

(0.5,2.25) and (-2,1)

Part C. Solve the system by graph

using a graphing tool

we know that

The solution of the non linear system is the intersection point both graphs

The intersection points are (0.5,2.25) and (-2,1)

therefore

The solutions are the points (0.5,2.25) and (-2,1)

see the attached figure

8 0

4 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!!!

Sloan [31]

Step-by-step explanation:

a^2+b^2=c^2

10^2+b^2=17^2

100+b^2=289

-100 -100

b^2= 189

b= the square root of 189

b=13.7477270849

7 0

3 years ago

WILL PAY 40 POINTS AND BRAINLIEST!!!!

Elan Coil [88]

Answer:

Part A)

The slope is 3.

Part B)

$\displaystyle y-1=3(x+3)$

Part C)

$\displaystyle y=3x+10$

Step-by-step explanation:

We know that the line goes through the points (-3, 1) and (-2, 4).

Part A)

To find the slope of a line given two points, we can use the slope formula:

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Where (x₁, y₁) and (x₂, y₂) are our two points.

So, let’s let (-3, 1) be (x₁, y₁) and let (-2, 4) be (x₂, y₂). Substitute appropriately:

$\displaystyle m=\frac{4-1}{-2-(-3)}$

Evaluate:

$\displaystyle m=\frac{3}{-2+3}=\frac{3}{1}=3$

Hence, the slope of our line is 3.

Part B)

Point-slope form is given by:

$\displaystyle y-y_1=m(x-x_1)$

Where m is our slope and (x₁, y₁) is a point.

So, let’s substitute 3 for m.

For our point, we can use either of the two given. Let’s use (-3, 1) for consistency. So, let (-3, 1) be (x₁, y₁). Therefore:

$\displaystyle y-1=3(x-(-3))$

Simplify. Hence, our point-slope form is:

$\displaystyle y-1=3(x+3)$

Part C)

To rewrite into slope-intercept form, we can just solve for y from our point-slope form. So, we have:

$\displaystyle y-1=3(x+3)$

Distribute on the right:

$\displaystyle y-1=3x+9$

Add 1 to boths sides. So, our slope-intercept equation is:

$\displaystyle y=3x+10$

5 0

3 years ago