Answer: 
Step-by-step explanation:
Given
Sample space is 
There are 8 element in sample space which indicates the outcome of tossing a coin three times
Probability of obtaining at least one head
D
Divide the whole thing by 2
2(X^2+8x-5)
X^2+8x. =5
Half of 8 is 4 sq it so you add 16
X^2+8x+16= 5+16
(X+4)^2=21
Answer: 12:5
Step-by-step explanation:
Answer:
3876
Step-by-step explanation:
Given the following :
Fraternity members = 20
They are to attend 5 different parties in groups of 4
Meaning a group = 4 persons
Atleast one brother will attend exactly one of the parties. (the brothers are indistinguishable).
Then, exactly one brother at a party (20 - 1) = 19, since they are indistinguishable.
Group members are in 4's
19C4
From: nCr = n! /(n-r)! r!
19C4 = 19! / (19 - 4)! 4!
= 19! / 15! 4!
= (19 * 18 * 17 * 16) / (4 * 3 * 2)
= 93024 / 24
= 3876
Answer:3t^2)^2. (3t2)2 ( 3 t 2 ) 2. Apply the product rule to 3t2 3 t 2 . 32(t2)2 3 2 ( t 2 ) 2. Raise 3 3 to the power of 2 2 . 9(t2)2 9 ( t 2 ) 2. Multiply the exponents in ...
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