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Talja [164]
3 years ago
5

A health conscious student faithfully wears a device that tracks his steps. Suppose that the distribution of the number of steps

he takes in a day is normally distributed with a mean of 10,000 and a standard deviation of 1,500 steps. What percent of the days does he exceed 13,000 steps
Mathematics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

2.28% of the days does he exceed 13,000 steps.

Step-by-step explanation:

We are given that  the distribution of the number of steps health conscious student takes in a day is normally distributed with a mean of 10,000 and a standard deviation of 1,500 steps.

<em>Let X = number of steps a health conscious student takes in a day</em>

So, X ~ N(\mu=10,000,\sigma^{2}=1,500^{2})

Now, the z score probability distribution is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean

            \sigma = standard deviation

So, percent of the days does he exceed 13,000 steps is given by = P(X > 13,000 steps)

    P(X > 13,000) = P( \frac{X-\mu}{\sigma} > \frac{13,000-10,000}{1,500} ) = P(Z > 2) = 1 - P(Z \leq 2)

                                                                  = 1 - 0.97725 = 0.0228 or 2.28%

Therefore, 2.28% of the days does he exceed 13,000 steps.

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