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lord [1]
3 years ago
15

1

Mathematics
1 answer:
Allisa [31]3 years ago
8 0

Answer:

-200 represents the price it orignally cost??

Step-by-step explanation:

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Given : circle x with radius r and circle y with radius s
tigry1 [53]

Answer:

we need to know the variables

Step-by-step explanation:


5 0
3 years ago
Which auto insurance coverage pays for injury or damage that the insured driver causes to other people or their property?
pashok25 [27]

Bodily injury liability and property damage liability is the auto insurance coverage that pays for injury or damage that the insured driver causes to other people or their property

To add, bodily injury liability also provides a legal defense in the event that you are sued for damages. Also, property damage liability<span> <span>coverage helps pay for the </span></span>damage<span> <span>that you cause to another vehicle, or other types of </span></span>property<span>.<span> </span></span>

3 0
3 years ago
Read 2 more answers
Last one - Thank you an advance :)
Ivan
Answers:
a. Given
b. Transitive property of congruence
c. Vertical angles are congruent
d. Transitive property of congruence

Let me know if you need any clarification as to how I got those answers. They should be self-explanatory but I'm happy to clarify further if needed. 

5 0
3 years ago
Read 2 more answers
Dana has $25, she went to the store and spent $10. She then received $50 for a birthday present. Dana was excited until she real
MissTica

Dana:

Starts with 25 = 25

Spends 10 = 25 - 10 = 15

Received 50 = 15 + 50 = 65

New tires cost 75 = 65 - 75 = -10

Tracey:

Starts with 50 = 50

Gets gas for 25 = 50 - 25 = 25

Received 100 = 25 + 125 = 125

Purchased boots for 150 = 125 - 150 = -25

Tracey ends up with the least amount of money after their purchases.

Hope this helps! :)

8 0
3 years ago
Read 2 more answers
In the triangle pictured, let A, B, C be the angles at the three vertices, and let a,b,c be the sides opposite those angles. Acc
Troyanec [42]

Answer:

Step-by-step explanation:

(a)

Consider the following:

A=\frac{\pi}{4}=45°\\\\B=\frac{\pi}{3}=60°

Use sine rule,

\frac{b}{a}=\frac{\sinB}{\sin A}&#10;\\\\=\frac{\sin{\frac{\pi}{3}}&#10;}{\sin{\frac{\pi}{4}}}\\\\=\frac{[\frac{\sqrt{3}}{2}]}{\frac{1}{\sqrt{2}}}\\\\=\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{1}=\sqrt{\frac{3}{2}}

Again consider,

\frac{b}{a}=\frac{\sin{B}}{\sin{A}}&#10;\\\\\sin{B}=\frac{b}{a}\times \sin{A}\\\\\sin{B}=\sqrt{\frac{3}{2}}\sin {A}\\\\B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Thus, the angle B is function of A is, B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Now find \frac{dB}{dA}

Differentiate implicitly the function \sin{B}=\sqrt{\frac{3}{2}}\sin{A} with respect to A to get,

\cos {B}.\frac{dB}{dA}=\sqrt{\frac{3}{2}}\cos A\\\\\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos A}{\cos B}

b)

When A=\frac{\pi}{4},B=\frac{\pi}{3}, the value of \frac{dB}{dA} is,

\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos {\frac{\pi}{4}}}{\cos {\frac{\pi}{3}}}\\\\=\sqrt{\frac{3}{2}}.\frac{\frac{1}{\sqrt{2}}}{\frac{1}{2}}\\\\=\sqrt{3}

c)

In general, the linear approximation at x= a is,

f(x)=f'(x).(x-a)+f(a)

Here the function f(A)=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

At A=\frac{\pi}{4}

f(\frac{\pi}{4})=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{\frac{\pi}{4}}]\\\\=\sin^{-1}[\sqrt{\frac{3}{2}}.\frac{1}{\sqrt{2}}]\\\\\=\sin^{-1}(\frac{\sqrt{2}}{2})\\\\=\frac{\pi}{3}

And,

f'(A)=\frac{dB}{dA}=\sqrt{3} from part b

Therefore, the linear approximation at A=\frac{\pi}{4} is,

f(x)=f'(A).(x-A)+f(A)\\\\=f'(\frac{\pi}{4}).(x-\frac{\pi}{4})+f(\frac{\pi}{4})\\\\=\sqrt{3}.[x-\frac{\pi}{4}]+\frac{\pi}{3}

d)

Use part (c), when A=46°, B is approximately,

B=f(46°)=\sqrt{3}[46°-\frac{\pi}{4}]+\frac{\pi}{3}\\\\=\sqrt{3}(1°)+\frac{\pi}{3}\\\\=61.732°

8 0
3 years ago
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